The following data refers to yield of tomatoes (kg/plot) for four different levels of salinity. Salinity level here refers to electrical conductivity (EC), where the chosen levels were EC = 1.6, 3.8, 6.0, and 10.2 nmhos/cm. (Usei = 1, 2, 3, and 4 respectively.)1.6: 59.8 53.5 56.163.6 58.23.8: 55.3 59.3 52.8 54.56.0: 51.4 48.2 53.948.610.2: 44.7 48.840.847.2 46.1n USE SALTApply the modified Tukey's method to identify significant differences among u's. (Round your answers to two decimal places.)W12W13 =W14 =W23 =W24 =W34 =Which pairs are significantly different? (Select all that apply.)O the 1.6 group and the 3.8 groupO the 1.6 group and the 6.0 groupO the 1.6 group and the 10.2 groupO the 3.8 group and the 6.0 groupO the 3.8 group and the 10.2 groupO the 6.0 group and the 10.2 groupO There are no significant differences.

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Answered: The following data refers to yield of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The following data refers to yield of tomatoes (kg/plot) for four different levels of salinity. Salinity level here refers to electrical conductivity (EC), where the chosen levels were EC = 1.6, 3.8, 6.0, and 10.2 nmhos/cm. (Use i = 1, 2, 3, and 4 respectively.) 1.6: 59.1 53.1 56.9 63.8 58.1 3.8: 55.6 59.1 52.8 54.1 6.0: 51.6 48.6 53.5 49.2 10.2: 44.7 48.9 40.9 47.5 46.5 Calculate the test statistic. (Round your answer to two decimal places.)
The following data refers to yield of tomatoes (kg/plot) for four different levels of salinity. Salinity level here refers to electrical conductivity (EC), where the chosen levels were EC = 1.6, 3.8, 6.0, and 10.2 nmhos/cm. (Use i = 1, 2, 3, and 4 respectively.) 1.6: 59.3 53.9 56.5 63.1 58.6 3.8: 55.4 59.9 52.2 54.6 6.0: 51.2 48.3 53.1 48.9 10.2: 44.7 48.2 41.1 47.1 46.9 Use the F test at level a = 0.05 to test for any differences in true average yield due to the different salinity levels. State the appropriate hypotheses. Hạ: at least two us are equal O Ho: H = z = 43 = Ha H: all four u,'s are unequal O Ho: H = uz = H3 - Ha Hạ: at least two 4's are unequal H: all four u,'s are equal Calculate the test statistic. (Round your answer to two decimal places.)
An experiment was conducted to study the extrusion process of biodegradable packaging foam. Two of the factors considered for their effect on the foam diameter (mm) were the die temperature(145°C vs.155°C) and the die diameter (3 mm vs. 4 mm). The results are in the accompanying data table. The question are attached in a photo
The following data refers to yield of tomatoes (kg/plot) for four different levels of salinity. Salinity level here refers to electrical conductivity (EC), where the chosen levels were EC = 1.6, 3.8, 6.0, and 10.2 nmhos/cm. (Use i = 1, 2, 3, and 4 respectively.) 1.6: 59.9 53.5 56.7 63.2 58.6 3.8: 55.6 59.6 52.6 54.5 6.0: 51.2 48.6 53.8 48.9 10.2: 44.3 48.4 41.0 47.9 46.5 In USE SALT Use the F test at level a = 0.05 to test for any differences in true average yield due to the different salinity levels. State the appropriate hypotheses. O Ho: H1 = H2 = !3 = H4 H: all four u's are unequal O Ho: H1 = H2 = H3 = H4 H: at least two u's are unequal O Ho: H1 # Hq # Hz# H4 H: all four u's are equal O Ho: H1* H2 * H3# H4 H: at least two u's are equal Calculate the test statistic. (Round your answer to two decimal places.) f = What can be said about the P-value for the test? O P-value > 0.100 O 0.050 < p-value < 0.100 O 0.010 < p-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001
The following data refers to yield of tomatoes (kg/plot) for four different levels of salinity. Salinity level here refers to electrical conductivity (EC), where the chosen levels were EC = 1.6, 3.8, 6.0, and 10.2 nmhos/cm. (Use i = 1, 2, 3, and 4 respectively.) 1.6: 59.4 53.4 56.3 63.2 58.4 3.8: 55.9 59.7 52.7 54.2 6.0: 51.7 48.2 53.9 49.0 10.2: 44.3 48.3 40.7 47.2 46.7 W23 = W 24 = W34 = USE SALT Apply the modified Tukey's method to identify significant differences among us. (Round your answers to two decimal places.) W12 = W13 = W14= Which pairs are significantly different? (Select all that apply.) Othe group and the 3.8 group the 1.6 group and the 6.0 group the 1.6 group and the 10.2 group the 3.8 group and the 6.0 group the 3.8 group and the 10.2 group O the 6.0 group and the 10.2 group There are no significant differences.
The following are the cystatin C levels (mg/L) for the patients described in Exercise 15 (A-17).Cystatin C is a cationic basic protein that was investigated for its relationship to GFR levels. In addition, creatinine levels are also given. (Note: Some subjects were measured more thanonce.) Cystatin C (mg/L) Creatinine (mmol/L) 1.78 4.69 0.35 0.14 2.16 3.78 0.30 0.11 1.82 2.24 0.20 0.09 1.86 4.93 0.17 0.12 1.75 2.71 0.15 0.07 1.83 1.76 0.13 0.12 2.49 2.62 0.14 0.11 1.69 2.61 0.12 0.07 1.85 3.65 0.24 0.10 1.76 2.36 0.16 0.13 1.25 3.25 0.17 0.09 1.50 2.01 0.11 0.12 2.06 2.51 0.12 0.06 2.34Source: D. M. Z. Krieser, M.D. Used with permission.(a) For each variable, compute the mean, median, variance, standard deviation, and coefficient ofvariation.(b) For each variable, construct a stem-and-leaf display and a box-and-whisker plot.(c) Which set of measurements is more variable, cystatin C or creatinine? On what do you baseyour answer? that question from…
Calcium is essential to tree growth because it promotes the formation of wood and maintains cell walls. In 1990, the concentration of calcium in precipitation in a certain area was 0.15 milligrams per liter (mg/L). A random sample of 10 precipitation dates in 2007 results in the following data table. Complete parts (a) through (c) below. Click the icon to view the data table. (a) State the hypotheses for determining if the mean concentration of calcium precipitation has changed since 1990. Но Ho: 0.15 mg/L H1: 0.15 mg/L i Data Table (b) Construct a 95% confidence interval about the sample mean concentration of calcium precipitation. The lower bound is The upper bound is (Round to four decimal places as needed.) 0.237 0.067 0.224 0.126 0.081 0.131 0.075 0.171 0.314 0.091 (c) Does the sample evidence suggest that calcium concentrations have changed since 1990? Print Done A. Yes, because the confidence interval does not contain 0.15 mg/L. B. Yes, because the confidence interval contains…
Find mZG. I 5/3 mZG = Submit % W
aChen -. M Gmail YouTube Maps oscar - Google D... Translate New Tab ece Gler 2/6 100% SID: 2. A researcher is studying the relationship between various properties of wine and their taste characteristics. The histogram below shows the amount of residual sugar (sugar left after fermentation) in a collection of wines. However, one of the bars, between 3 and 5 grams per liter, is missing. 50 (47.9) (38.7) 30 10 (0.1) (0.92) (0.1) 2 10 15 Residual sugar (grams/liter) Calculate the height of the missing bar and draw it in. (Show your work below, and indicate the numerical value in parentheses above the bar.) % per gramlter
Roman, a health data officer, was tasked to create a report describing the height of all the children ages 12-15 years in a small town in Rome. He measured the height of all the 37 children (ages 12-15 years) in that small town. Answer the table showing the number and percentage of children ages 12 to 15 years according to sex. Sex f Rel f Male <2 decimal places> Female <2 decimal places> Σf <2 decimal places>
A sociologist wants to determine if the life expectancy of people in Africa is less than the life expectancy of people in Asia. The data obtained is shown in the table below. Africa Asia = 63.3 yr. 1 X,=65.2 yr. 2 o, = 9.1 yr. = 7.3 yr. n1 = 120 = 150
The following are the cystatin C levels (mg/L) for the patients described in Exercise 15 (A-17).Cystatin C is a cationic basic protein that was investigated for its relationship to GFR levels. Inaddition, creatinine levels are also given. (Note: Some subjects were measured more than once.)Cystatin C (mg/L) Creatinine (mmol/L)1.78 4.69 0.35 0.142.16 3.78 0.30 0.111.82 2.24 0.20 0.091.86 4.93 0.17 0.121.75 2.71 0.15 0.071.83 1.76 0.13 0.122.49 2.62 0.14 0.111.69 2.61 0.12 0.071.85 3.65 0.24 0.101.76 2.36 0.16 0.131.25 3.25 0.17 0.091.50 2.01 0.11 0.122.06 2.51 0.12 0.062.34Source: Data provided courtesy of D. M. Z. Krieser, M.D.(a) For each variable, compute the mean, median, variance, standard deviation, and coefficient ofvariation.(b) For each variable, construct a stem-and-leaf display and a box-and-whisker plot.(c) Which set of measurements is more variable, cystatin C or creatinine? On what do you base youranswer?

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