The fat, glyceryl trioleate (C57H10406), is metabolized via the following reaction. Given the enthalpies of formation, calculate the energy (kJ) when 1.00 g of this fat reacts. C57H10406(s) + 80 O2(g) ---> 57 CO2(g) + 52 H2O(1) AH;° C57H10406 = -70870 kJ/mole AH;° H2O(1) = -285.8 kJ/mole AH;° CO2(g) = -393.5 kJ/mole %3D 40.4 33.4 37.9 42.6 30.2

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