The electric flux through the face a cube with sides of length 7.2 mm is measured to be 3.9x10- 4 Nm²/C. Assuming a uniform field determine the magnitude of the field (in N/C) through cube face.

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Chapter6: Gauss's Law
Section: Chapter Questions
Problem 55P: The electric field 10.0 cm from the surface of a copper ball of radius 5.0 cm is directed toward the...
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The electric flux through the face a cube with sides
of length 7.2 mm is measured to be 3.9x10-
4 Nm²/C. Assuming a uniform field determine the
magnitude of the field (in N/C) through cube face.
Transcribed Image Text:The electric flux through the face a cube with sides of length 7.2 mm is measured to be 3.9x10- 4 Nm²/C. Assuming a uniform field determine the magnitude of the field (in N/C) through cube face.
Two spheres, each of radius R, have volume charge
densities 5.4 €/m³ and -5.4 C/m³
3
respectively. The positively charged sphere is
centered at the origin, while the negatively charged
sphere is centered along the x-axis at at 9.4 m .î.
Note that the spheres are overlapping (R> (9.4
m)). What is the magnitude of the electric field in
this region of overlap in units of tera N/C?
Recall that the electric field inside a single
uniformly charged sphere can be calculated using
Gauss' law to be
Ē P
=
-7,
3€0
and that electric fields should be added as vectors.
(Also, remember that tera is 10¹2)
Transcribed Image Text:Two spheres, each of radius R, have volume charge densities 5.4 €/m³ and -5.4 C/m³ 3 respectively. The positively charged sphere is centered at the origin, while the negatively charged sphere is centered along the x-axis at at 9.4 m .î. Note that the spheres are overlapping (R> (9.4 m)). What is the magnitude of the electric field in this region of overlap in units of tera N/C? Recall that the electric field inside a single uniformly charged sphere can be calculated using Gauss' law to be Ē P = -7, 3€0 and that electric fields should be added as vectors. (Also, remember that tera is 10¹2)
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