The derivative of the power series f(x)= 2 n=0 * (-1)"(2-5.8. (3n+2))(x- 1)2n 3n. (n² +1) %3D is f(x) = E * (- 1)"(2 -5-8 (3n+2)) 2n (x-1)2n-1 3n. (n² +1) n=0 True False

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter1: Equations And Inequalities
Section1.CT: Chapter Test
Problem 5CT: Solve for x: z=x.
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(-1)"(2-5-8 . (3n+2))(x-1)²n
3n. (n² +1)
The derivative of the power series f(x)= 2
%3D
is
(-1)"(2 ·5·8. (3n+2)) · 2n· (x- 1)2n-1
3n. (n² + 1)
f(x) = E
%3D
n=0
True
False
QUESTION 9
For the function f(x)=
=, the first four derivatives evaluated at a =4 are:
%3D
„Dx+1
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Transcribed Image Text:(-1)"(2-5-8 . (3n+2))(x-1)²n 3n. (n² +1) The derivative of the power series f(x)= 2 %3D is (-1)"(2 ·5·8. (3n+2)) · 2n· (x- 1)2n-1 3n. (n² + 1) f(x) = E %3D n=0 True False QUESTION 9 For the function f(x)= =, the first four derivatives evaluated at a =4 are: %3D „Dx+1 Click Save and Submit to save and submit. Click Save All Answers to save all answers.
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