The concentration of is given in the follor is given in the following table: \table[[in, [NO]10² mol m ΝΟ -3 *dm ,In(- -ol*dm m 0 10 20 30 40 50 60 70 80 90 100 [m³) → products, ...ncentration of the reactants is equal to a. (b) The concentration of [N₂O5] and in[N₂O5] as a function of time for the reaction N₂O5 (g) → 2 NO2 (g) + 2 O₂ (g) at 318 K is given in the following table: t/min [N₂O,V/10-2 mol-dm-³ 1.24 0.92 0.68 0.50 0.37 0.28 0.20 0.15 0.11 3 0.08 0.06 y reaction: In([N,O,1/mol-dm^³) <-4.39 -4.69 <-4.99 <-5.30 -5.60 -5.88 -6.21 <-6.50 <-6.81 -7.13 -7.42 Without using graphs and assuming first-order rate law, find out mathematically the slope of the plot of In[N₂O5]/mol.dm³ vs. t/min. (Marks = 2 + 3 = 5) 9. (a) Discuss how...

Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.81PAE
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The concentration of is given in the follor is given in the following table: \table[[in, [NO]10² mol
m
ΝΟ
-3
*dm ,In(- -ol*dm
m
0
10
20
30
40
50
60
70
80
90
100
[m³)
→ products,
...ncentration of the reactants is equal to a.
(b) The concentration of [N₂O5] and in[N₂O5] as a function of time for the reaction
N₂O5 (g) → 2 NO2 (g) + 2 O₂ (g) at 318 K
is given in the following table:
t/min [N₂O,V/10-2 mol-dm-³
1.24
0.92
0.68
0.50
0.37
0.28
0.20
0.15
0.11
3
0.08
0.06
y reaction:
In([N,O,1/mol-dm^³)
<-4.39
-4.69
<-4.99
<-5.30
-5.60
-5.88
-6.21
<-6.50
<-6.81
-7.13
-7.42
Without using graphs and assuming first-order rate law, find out mathematically the slope of
the plot of In[N₂O5]/mol.dm³ vs. t/min. (Marks = 2 + 3 = 5)
9. (a) Discuss how...
Transcribed Image Text:The concentration of is given in the follor is given in the following table: \table[[in, [NO]10² mol m ΝΟ -3 *dm ,In(- -ol*dm m 0 10 20 30 40 50 60 70 80 90 100 [m³) → products, ...ncentration of the reactants is equal to a. (b) The concentration of [N₂O5] and in[N₂O5] as a function of time for the reaction N₂O5 (g) → 2 NO2 (g) + 2 O₂ (g) at 318 K is given in the following table: t/min [N₂O,V/10-2 mol-dm-³ 1.24 0.92 0.68 0.50 0.37 0.28 0.20 0.15 0.11 3 0.08 0.06 y reaction: In([N,O,1/mol-dm^³) <-4.39 -4.69 <-4.99 <-5.30 -5.60 -5.88 -6.21 <-6.50 <-6.81 -7.13 -7.42 Without using graphs and assuming first-order rate law, find out mathematically the slope of the plot of In[N₂O5]/mol.dm³ vs. t/min. (Marks = 2 + 3 = 5) 9. (a) Discuss how...
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