The cell 2- SCE// Ag₂ CrO4 (sat'd), CrO4 ²- (xM) /Ag is employed for the determination of pCrO4-. ESCE = 0.244 V at 25 OC The half reaction at indicator electrode Ag₂ CrO4 (s) + 2e- → 2 Ag (s) + CrO2- Eº = +0.446 V a) Calculate pCrO4 when the cell potential is 0.402 V b) What type of indicator electrode is Ag in this case?

Physical Chemistry
2nd Edition
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter8: Electrochemistry And Ionic Solutions
Section: Chapter Questions
Problem 8.10E: For each of the following reactions, determine the overall balanced electrochemical reaction, its...
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The cell
2-
SCE// Ag₂ CrO4 (sat'd), CrO4 ²- (xM) /Ag
is employed for the determination of pCrO4-.
ESCE = 0.244 V at 25 OC
The half reaction at indicator electrode
Ag₂ CrO4 (s) + 2e-
2 Ag (s) + CrO₂2- E0=+0.446 V
4
a) Calculate pCrO4 when the cell potential is 0.402 V
b) What type of indicator electrode is Ag in this case?
Transcribed Image Text:The cell 2- SCE// Ag₂ CrO4 (sat'd), CrO4 ²- (xM) /Ag is employed for the determination of pCrO4-. ESCE = 0.244 V at 25 OC The half reaction at indicator electrode Ag₂ CrO4 (s) + 2e- 2 Ag (s) + CrO₂2- E0=+0.446 V 4 a) Calculate pCrO4 when the cell potential is 0.402 V b) What type of indicator electrode is Ag in this case?
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