The armature shaft of a 50 kW, 580 rpm electric motor, mounted on two bearings A and B, is shown in Fig. The total magnetic pull on the armature is 5 kN and it can be assumed to be uniformly distributed over a length of 400 mm midway between the bearings. The shaft is made of steel with an ultimate tensile strength of 770 N/mm? and yield strength of 580 N/mm. Determine the shaft diameter using the ASME code if, k, = 1.5 and k, = 1.0 Assume that the pulley is keyed to the shaft. 150 10 N/mm 150 300 1000 N 3000 N

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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The armature shaft of a 50 kW, 580rpm
electric motor, mounted on two bearings A and
B, is shown in Fig. The total magnetic pull
on the armature is 5 kN and it can be assumed to
be uniformly distributed over a length of 400 mm
midway between the bearings. The shaft is made of
steel with an ultimate tensile strength of 770 N/mm?
and yield strength of 580 N/mm. Determine the
shaft diameter using the ASME code if,
k = 1.5 and k, = 1.0
Assume that the pulley is keyed to the shaft.
150
400
10 N/mm
150
300
B
1000 N
3000 N
Transcribed Image Text:The armature shaft of a 50 kW, 580rpm electric motor, mounted on two bearings A and B, is shown in Fig. The total magnetic pull on the armature is 5 kN and it can be assumed to be uniformly distributed over a length of 400 mm midway between the bearings. The shaft is made of steel with an ultimate tensile strength of 770 N/mm? and yield strength of 580 N/mm. Determine the shaft diameter using the ASME code if, k = 1.5 and k, = 1.0 Assume that the pulley is keyed to the shaft. 150 400 10 N/mm 150 300 B 1000 N 3000 N
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