terms of the time t. Also find the maximum values of 9. A sinusoidal e.m.f. 110 sin 400t volts is connected in series in a circuit with an inductance of 0.1 henry, a re sistance of 10 ohms, and a capacitance of 250(10) farad. Find the steady-state solutions of Q and the steady-state charge and current. Q = - 0.00275(3 sin 400t + cos 400t) I = 1,10(sin 400t - 3 cos 400t) %3D Qmax = 0.0087 coul. Imax = 3:48 amp.

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.1MCQ: The rms value of v(t)=Vmaxcos(t+) is given by a. Vmax b. Vmax/2 c. 2Vmax d. 2Vmax
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need answers asap, pls provide solutions as well. Thank you!

terms of the time t. Also find the maximum values of
sistance of 10 ohms, and a capacitance of 250(10)*
farad. Find the steady-state solutions of Q and I in
9. A sinusoidal e.m.f. 110 sin 400t volts is connected in
series in a circuit with an inductance of 0.1 henry, a r
farad. Find the steady-state solutions of Q and
the steady-state charge and current.
Q = - 0.00275(3 sin 400t + cos 400t)
I = 1,10(sin 400t-3 cos 400t)
= 0.0087 coul.
Qmax
Imax
= 3:48 amp.
Transcribed Image Text:terms of the time t. Also find the maximum values of sistance of 10 ohms, and a capacitance of 250(10)* farad. Find the steady-state solutions of Q and I in 9. A sinusoidal e.m.f. 110 sin 400t volts is connected in series in a circuit with an inductance of 0.1 henry, a r farad. Find the steady-state solutions of Q and the steady-state charge and current. Q = - 0.00275(3 sin 400t + cos 400t) I = 1,10(sin 400t-3 cos 400t) = 0.0087 coul. Qmax Imax = 3:48 amp.
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