Supply the missing constant, k, so that the resulting trinomial is a perfect square. Then factor the polynomial. Note that since the polynomial will be a perfect square, then 'Factor 1' and 'Factor 2' will be the same. x²+2x+p p= Factor 1 = Factor 2 = M M 0

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter5: Factoring Polynomials
Section5.6: Squares Of Binomials
Problem 22WE
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Supply the missing constant, k, so that the resulting trinomial is a perfect square. Then factor the polynomial. Note that since the polynomial will be a perfect
square, then 'Factor 1' and 'Factor 2' will be the same.
x²+2x+p
Р
Factor 1 =
Factor 2 =
Question 2:
Р
O
Supply the missing constant, k, so that the resulting trinomial is a perfect square. Then factor the polynomial. Note that since the polynomial will be a perfect
square, then 'Factor 1' and 'Factor 2' will be the same.
x²-2x+p
Factor 1 =
B
Factor 2 =
M
M
M
M
M
Transcribed Image Text:Supply the missing constant, k, so that the resulting trinomial is a perfect square. Then factor the polynomial. Note that since the polynomial will be a perfect square, then 'Factor 1' and 'Factor 2' will be the same. x²+2x+p Р Factor 1 = Factor 2 = Question 2: Р O Supply the missing constant, k, so that the resulting trinomial is a perfect square. Then factor the polynomial. Note that since the polynomial will be a perfect square, then 'Factor 1' and 'Factor 2' will be the same. x²-2x+p Factor 1 = B Factor 2 = M M M M M
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