Studies on a machine that molds plastic water pipe indicate that when it is injecting 25.76 mm diameter pipe, the process standard deviation is 0.75 mm. The pipe has a specification of 25.76 mm plus or minus 1.95 mm. What is the process capability index (Cp)? Оа. 0.4333 O b. 2.6 Ос. 1.733
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A: Formula:
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A: Given information: Defect rate (p) = 1.00% = 0.01Sample Size (n) = 400Standard Deviation (z) = 3
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A: N=8 Total no. of the samples = 706.3 x=706.38 = 88.29
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A: Solution UCL = 16+0.86 = 16.86 LCL = 16-0.86 = 15.14 For 3.2 quality rating use 3 sigma quality…
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A: Given, Lower Limit- 0.02 Upper Limit- 0.08
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A: THE ANSWER IS AS BELOW:
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A: SOLUTION: X BAR = 3 R BAR = 1.4 A2 value corresponding to N =5=0.58
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A: WE ARE ALLOWED TO DO ONE QUESTION ONLY. THE ANSWER IS AS BELOW:
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- Quality control in a factory pulls 40 parts with paint, packaging, or electronic defects from anassembly line. Of these, 28 had a paint defect, 17 had a packaging defect, 13 had an electronicdefect, 6 had both paint and packaging defects, 7 had both packaging and electronics defects, and 10had both paint and electronic defects. Did any part have all three types of defect? If so, how many?Linda Boardman, I nc., an equipment manufacturerin Boston, has submitted a sample cutoff valve to improve yourmanufacturing process. Your process engineering department basconducted experiments and found that the valve has a mean (J.L)of 8.00 and a standard deviation (cr) of .04. Your desired performanceis f..L = 8.0 ±3cr, where cr = .045. What is the Cpk of theBoardman valve?3.6. One of the stages in the process of making denim cloth at the Southern Mills Company is to spin cotton yarn onto spindles for subse- quent use in the weaving process. Occasionally the yarn breaks during the spinning process, and an operator ties it back together. Some num- ber of breaks is considered normal; however, too many breaks might mean that the yarn is of poor quality. In order to monitor this process, the quality-control manager randomly selects a spinning machine each hour and checks the number of breaks during a 15-minute period. Following is a summary of the observations for the past 20 hours: Number of Number of Sample Breaks Sample Breaks 1 3 11 3 2 12 4 3 4 13 4 1 14 7 5 15 8. 16 7 17 4 18 7. 8 19 8 9. 20 6. 10 Construct a c-chart using 3ơ limits for this process and indicate if the process was out of control at any time. ohoin when orders come into 3. 6
- The specifications for a manifold gasket that installs between two engine parts calls for a thickness of 2.750 mm ± .025 mm. The process is currently operating at a mean thickness of 2.75 mm. The standard deviation of the process is estimated to be 0.007 mm. The process is six-sigma capable. True FalseWest Battery Corp. has recently been receiving complaints from retailers that its 9-volt batteries are not lasting as long as other name brands. James West, head of the TQM program at West's Austin plant, believes there is no problem because his batteries have had an average life of 60hours, about 10% longer than competitors' models. To raise the lifetime above this level would require a new level of technology not available to West. Nevertheless, he is concerned enough to set up hourly assembly line checks. Previously, after ensuring that the process was running properly, West took samples of 5 9-volt batteries for 25 test to establish the standards for control chart limits. Those 25 tests are shown in the following table: Sample Data Sample Data Hour Sample Taken 1 2 3 4…Management at Webster Chemical Company is concerned as to whether caulking tubes are being properly capped. If a significant proportion of the tubes are not being sealed, Webster is placing its customers in a messy situation. Tubes are packaged in large boxes of 135. Several boxes are inspected, and the following numbers of leaking tubes are found: View an example Sample 1 2 3 Get more help. 4 Tubes 7 7 8 5 1 5 6 7 Calculate p-chart three-sigma control limits to assess whether the capping process is in statistical control. The UCL, equals 1 Sample 8 8 9 10 11 12 13 14 Tubes 7 2 4 8 6 9 MacBook Pro 3 Sample 15 16 17 18 19 20 Total Tubes 8 3 3 5 and the LCL equals (Enter your responses rounded to three decimal places. If your answer for LCL, is negative, enter this value as 0.) 3 6 104 Clear all Check answer O
- 3. Refer to Table S6.1 - Factors for Computing Control Chart Limits (3 sigma) LOADING... for this problem. Thirty-five samples of size 7 each were taken from a fertilizer-bag-filling machine at Panos Kouvelis Lifelong Lawn Ltd. The results were: Overall mean = 57.75 lb.; Average range R = 1.54 lb. a) For the given sample size, the control limits for 3-sigma x chart are: Part 2 Upper Control Limit (UCLx) = _______ lb. (round your response to three decimal places). Lower Control Limit (LCLx) = _______ lb. (round your response to three decimal places). B. the control limits for 3-sigma r chart are: Upper Control Limit (UCLr)= _______ lb. (round your response to three decimal places). Lower Control Limit(LCLr)= _______ lb. (round your response to three decimal places).An Xbar control chart designed with L=3 and sample size n=4 has control limits UCL=342.05 and LCL=317.95. If the mean shifts to mu1=335 beta is found to be 0.9603. What would be the ARL1 after the mean shifts to mu1? 4.2 10.06 2.03 not enough information 25.22Northshore hospital surgeon, Bill, wants to build 3-sigma x- bar control limits for the open heart surgery. The target value for the mean of the process (x-bar) is 10 units, and the standard deviation of the process is 8. If samples of size 16 are to be taken, what will be the upper and lower control limits, respectively? Question 33 options: 8 and 12 16 and 4 -8 and 28 18 and 6 16 and 4
- ble size, the control limits for 3-sigma x chart are: mit (UCL) = lb. (round your response to three decimal places). mit (LCL) = for the 3-sigma R imit (UCLR)= Limit (LCLR)= Definition Sample Size, n 2345678982 10 12 Mean Factor, A2 1.88 1.023 0.729 0.577 0.483 0.419 0.373 0.337 0.308 0.266 Print Upper Range, 4 3.268 2.574 2.282 2.115 2.004 1.924 1.864 1.816 1.777 1.716 Done Lower Range, D3 0 0 0 0 0 0.076 0.136 0.184 0.223 0.284 - XThe measurement of 85 automotive cables gave an arithmetic mean of the inner diameters of 3.51 mm and a standard deviation of 0.02 mm.The value required by the manufacturer is 3.5 upper/lower tolerance +0.04/ -0.12It is requested : a. Calculate the capability coefficients Cp, Cpk and state whether or not the machine is capable of producing compliant parts, i.e. whether or not the data dispersion is well centred. If applicable, calculate the adjustment coefficient Cr.b. If scrap is obtained, state whether it is recoverable or non-recoverable and calculate the percentage of scrap.c. Plot the limits of the tolerance field and the distribution of the measured data (using mean and standard deviation).Lay's potato chip filling process has a lower specification limit of 9.5 oz. and an upper specification of 10.5 oz. The mean is 10 oz. What should be the value for standard deviation in this process to achieve a ppm of 5110? A. 0.1786 B. 0.2675 OC. 0.4453 OD. 0.3564