State the order of evaluation of the operators in each of the following C statements andshow the value of x after each statement is performed.a) x = 7 + 3 * 6 / 2 - 1;b) x = 2 % 2 + 2 * 2 - 2 / 2;c) x = ( 3 * 9 * ( 3 + ( 9 * 3 / ( 3 ) ) ) );
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State the order of evaluation of the operators in each of the following C statements and
show the value of x after each statement is performed.
a) x = 7 + 3 * 6 / 2 - 1;
b) x = 2 % 2 + 2 * 2 - 2 / 2;
c) x = ( 3 * 9 * ( 3 + ( 9 * 3 / ( 3 ) ) ) );
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- 5. (Algebra: solve 2 X 2 linear equations) You can use Cramer's rule to solve the following 2 X 2 system of linear equation: ax + by = e cx + dy = f ● x = ed - bf bc ad y = af - ec ad bc - Write a program that prompts the user to enter a, b, c, d, e, and f and display the result. If ad- bc is 0, report that The equation has no solution. Enter a, b, c, d, e, f: 9.0, 4.0, 3.0, -5.0, -6.0, -21.0 Enter x is -2.0 and y is 3.0 Enter a, b, c, d, e, f: 1.0, 2.0, 2.0, 4.0, 4.0, 5.0 Enter The equation has no solutionwhy are the following statements NOT considered to be disjunctive normal form? A * (B + ~C) ~(A + B)Rewrite the following statements using combined assignment operators: length = length / 2;
- 6. B) Write equivalent expressions for each of the following by using De Morgan’s Law. !(a || b) !(y > 2 && !found )int power(int base,int exp); *This function accepts the arguments for base and exponent and returns power. The algorithm is to repeatedly multiply the value of the base to how many time the value of exponent.* For example: Test Input Result printf("%d",power(2,5)); 2 32 5 printf("%d",power(3,4)); 3 81 4 -Use C language, please. Thank you.Write C assignment statements for the following: a. Assign a value of 0 to a variable called between if n is less than -k or greater than +k; otherwise, assign 1. b. Assign a value of 1 to a variable called divisor if digit is a divisor of num; otherwise, assign a value of 0. c. Assign a value of 1 to a variable called lowercase if ch is a lowercase letter; otherwise, assign a value of 0.
- a) Prove the assignment segment given below to its pre-condition and post-condition using Hoare triple method. (t >= 5} void main () int f,g, z; z = 2 *t - g = 2 * z; f = 2 * 8; a - 5; (f >= 3)Rewrite the following statements using combined assignment operators: count = count + 1;can obtain the remainder of this division by using the % operator. For example, 10 % 3 is 1. In C++, the % can be applied only to integer operands; it cannot be applied to floating-point types. The following program demonstrates the modulus operator: