State the null and alternative hypotheses. H₂₁:0² = 1 H₂:0² #1 H₂₁:0² > 1 H₂:0² $1 H₁:0² <1 H₂:0² 21 OH₁: 0² 51 H₂:0² > 1 H₂:0² 21 H₂:0² <1 Find the value of the test statistic. Find the p-value. (Round your answer to four decimal places.) p-value= State your conclusion. O Do not reject H. We can conclude that o² > 1. O Reject H. We cannot conclude that ² > 1. O Do not reject H. We cannot conclude that o² > 2 > 1. O Reject H. We can conclude that 2² > 1.

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter1: Functions
Section1.2: The Least Square Line
Problem 8E
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City Trucking, Inc., claims consistent delivery times for its routine customer deliveries. A sample of 23 truck deliveries shows a sample variance of 1.6. Test to determine whether H: ² s 1 can
be rejected. Use a = 0.10.
State the null and alternative hypotheses.
H₂₁:0² = 1
: 0² # 1
0 H₂:0² > 1
H₂:0² s1
O
H₂:0² 21
H: ² s1
O
H₂:0² > 1
0 H₁:0² 21
H₂:0² <1
Find the value of the test statistic.
Find the p-value. (Round your answer to four decimal places.)
p-value =
State your conclusion.
O Do not reject H. We can conclude that o² > 1.
Reject H. We cannot conclude that o² > 1.
O Do not reject H. We cannot conclude that ² > 1.
O Reject H. We can conclude that ² > 1.
Transcribed Image Text:City Trucking, Inc., claims consistent delivery times for its routine customer deliveries. A sample of 23 truck deliveries shows a sample variance of 1.6. Test to determine whether H: ² s 1 can be rejected. Use a = 0.10. State the null and alternative hypotheses. H₂₁:0² = 1 : 0² # 1 0 H₂:0² > 1 H₂:0² s1 O H₂:0² 21 H: ² s1 O H₂:0² > 1 0 H₁:0² 21 H₂:0² <1 Find the value of the test statistic. Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. O Do not reject H. We can conclude that o² > 1. Reject H. We cannot conclude that o² > 1. O Do not reject H. We cannot conclude that ² > 1. O Reject H. We can conclude that ² > 1.
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