SORU-11) Bog birakBMAli sits at one end of a canoe having mass of M and length of L.Consider Ali as a point mass of m. Ali and the canoe are initiallyat rest with respect to the shoreline. Ali stands up and walks to thepoint that is L / 6 away from CM. Assume the canoe moveswithout friction on the lake surface. How far does the canoe movefrom shore when Ali reaches the point that is L/ 6 away from CMof the canoe?mlA-)M+mmLB-)2(M+m)2mlC-)3(M+m)5mlD-)6(M+m)3mlE-)4(M+m)

Answered: SORU-11 ) Bog birak B M Ali sits at one…

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter4: The Laws Of Motion

Section: Chapter Questions

Problem 61AP: A boy coasts down a hill on a sled, reaching a level surface at the bottom with a speed of 7.00 m/s....

See similar textbooks

Related questions

Question

SORU-11
) Bog birak
B
M
Ali sits at one end of a canoe having mass of M and length of L.
Consider Ali as a point mass of m. Ali and the canoe are initially
at rest with respect to the shoreline. Ali stands up and walks to the
point that is L / 6 away from CM. Assume the canoe moves
without friction on the lake surface. How far does the canoe move
from shore when Ali reaches the point that is L/ 6 away from CM
of the canoe?
ml
A-)
M+m
mL
B-)
2(M+m)
2ml
C-)
3(M+m)
5ml
D-)
6(M+m)
3ml
E-)
4(M+m)

Expert Solution

Step 1 :Introduction

Initially as the boat and the person A are at rest , but when the person starts to walk the boat will also move due to the frictional force exerted by the person on the boat ,which means the force resulting the motion is internal .Thus the center of mass $(x)$ will be at the same for both ,that is , $\begin{array}{rcl} ∆ x & = & M_{t o t a l} r_{1} - m r_{2} \\ = & 0 \end{array}$ , where $M_{t o t a l} = M + m$ is the mass of canoe-person system, M is the mass of the canoe and m is the mass of person A , $r_{1} = x$ is the distance the system travelled , L is the length of the canoe and $\begin{array}{rcl} r_{2} & = & L - \frac{L}{6} \\ = & \frac{6 L - L}{6} \\ = & \frac{5 L}{6} \end{array}$ is the distance the person travelled.

Step 2 :Calculation of the distance travelled

Calculate the distance travelled by the canoe-person system by using the relation $\begin{array}{rcl} M_{t o t a l} r_{1} - m r_{2} & = & 0 \\ (M + m) r_{1} & = & m r_{2} \end{array}$ , where M is the mass of the canoe and m is the mass of person A , $r_{1} = x$ is the distance the system travelled , L is the length of the canoe and $\begin{array}{rcl} r_{2} & = & \frac{5 L}{6} \end{array}$ is the distance the person travelled.