Kindly add label and box for the final answer thank you! QUESTION 3ProblemA moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done Win terms of K1?SolutionTo solve for the work done, first we must determine what is the final kinetic energy of the electron.By concept, we know thatK=(1/2)mv²1K2=(1/2)mv2But it was mentioned that:v2=(v1so, K2 in terms of v1 isK2=(mv21Substituting the expression for K1 results toK2=(K1Since work done isW=AK=KEvaluating results toW=(K1

Answered: Solution To solve for the work done,…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter9: Energy In Nonisolated Systems

Section: Chapter Questions

Problem 32PQ

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Thor stands on the top of stark tower 425 m adn fights his brother loki using mjolnir his hammer. if his hammer has a mass equal to 300 billion elephants cal it 4.5*10^15 kg what i the gaviation potential energy in J of jjolnir relative to the ground? use scientific notation to enter you answer. B. Loki tricks thor into dropping Mjolnir off stark tower. when the hammer has fallen one third of the way down the tower what is its kinetic energy in J? Hint you could find the speed then calculate the kinetic energy but there's an easier way...
Problem A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done Win terms of K1? Solution To solve for the work done, first we must determine what is the final kinetic energy of the electron. By concept, we know that K1=(1/2)mv²1 K2=(1/2)my2 But it was mentioned that: v2=( v1 so, K2 in terms of v1 is K2=( )mv², Substituting the expression for K1 results to K2=( Since work done is W=AK=K -K Evaluating results to W=( K1
Problem A moving electron has a Kinetic Energy Kq. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done Win terms of Kq? Solution To solve for the work done, first we must determine what is the final kinetic energy of the electron. By concept, we know that K1=(1/2)mv21 K2=(1/2)mv2 But it was mentioned that: v2=( so, K2 in terms of vq is K2=( )mv²1 Substituting the expression for K1 results to K2=( K1 Since work done is W=AK=K -K Evaluating results to W=( K1
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