so shouldn't you use the formula V=Vs(e^(-t/RC)) instead of the formula V=Vs(1-e^(-t/RC)), which is for charging capacitors? Please correct me and tell me why if I'm wrong. Thank you!

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For b of this question, I think it's using the wrong formula. The question itself specifically states that capacitors are discharging, so shouldn't you use the formula V=Vs(e^(-t/RC)) instead of the formula V=Vs(1-e^(-t/RC)), which is for charging capacitors? Please correct me and tell me why if I'm wrong. Thank you!

Textbook Problem
At time t= 0, an RC circuit consists of a 12.0-V emf device, a 60.0-2
resistor, and a 150.0-µF capacitor that is fully charged. The switch
is thrown so that the capacitor begins to discharge.
a. What is the time constant t of this circuit?
b. How much charge is stored by the capacitor at t= 0.5t, 2t, and
4т?
Transcribed Image Text:Textbook Problem At time t= 0, an RC circuit consists of a 12.0-V emf device, a 60.0-2 resistor, and a 150.0-µF capacitor that is fully charged. The switch is thrown so that the capacitor begins to discharge. a. What is the time constant t of this circuit? b. How much charge is stored by the capacitor at t= 0.5t, 2t, and 4т?
Write the expression for potential across the capacitor in RC series
circuit with respect to time constant as.
Ve = V, (1 – e(-iRC)
(II)
Here, V. is the capacitor volatge, V3 is the emf device volatge, R is
the circuit resisitance, C is the circuit capcitance and t is the time
in s.
Write the expression for charge stored in capacitor as.
Q = CVc
(III)
Here, Q is charge store in capacitor, C is the circuit capcitance and
Ve is the capacitor volatge.
Conclusion:
Substitute 12.0 V for Vs, 150.0 µF for C, 60.0 2 for R and 0.5t for t in
equation (II).
Transcribed Image Text:Write the expression for potential across the capacitor in RC series circuit with respect to time constant as. Ve = V, (1 – e(-iRC) (II) Here, V. is the capacitor volatge, V3 is the emf device volatge, R is the circuit resisitance, C is the circuit capcitance and t is the time in s. Write the expression for charge stored in capacitor as. Q = CVc (III) Here, Q is charge store in capacitor, C is the circuit capcitance and Ve is the capacitor volatge. Conclusion: Substitute 12.0 V for Vs, 150.0 µF for C, 60.0 2 for R and 0.5t for t in equation (II).
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