SITUATION III: The cross section of a tension member is shown below: Use Fy=275 MPa, Fu=400 MPa. 25 350 16 mm o 30 25 350 12. Compute for the gross area of the cross section. a. 28 000 mm2 C. 23 490 mm? b. 29750 mm? d. 23000 mm? 13. Compute for the allowable tensile capacity due to yielding. a. 4698.00 kN b. 4654.39 kN - C. 4610.78 kN d. 6706.59 kN 14. Compute for effective net area if shear lag factor is 0.90. Diameter of holes is 3mm more than that of bolts. a. 28 000 mm? c. 23 490 mm? b. 29750 mm? d. 23000 mm? 15. Compute for the allowable tensile capacity due to rupture. b. 4654.39 kN d. 6706.59 kN a. 4698.00 kN C. 4610.78 kN 16. Compute for the safe load that could be carried by the tension member. a. 4698.00 kN b. 4654.39 kN C. 4610.78 kN d. 6706.59 kN

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Answer 15&16
SITUATION III:
The cross section of a tension member
is shown below: Use Fy=275 MPa,
Fu=400 MPa.
25
350
16 mm O
30
25
350
12. Compute for the gross area of the
cross section.
a. 28 000 mm²
C. 23 490 mm?
b. 29750 mm²
d. 23000 mm?
13. Compute for the allowable tensile
capacity due to yielding.
a. 4698.00 kN
b. 4654.39 kN
- C. 4610.78 kN
d. 6706.59 kN
14. Compute for effective net area if
shear lag factor is 0.90. Diameter of
holes is 3mm more than that of bolts.
a. 28 000 mm?
C. 23 490 mm?
b. 29750 mm?
d. 23000 mm?
15. Compute for the allowable tensile
capacity due to rupture.
b. 4654.39 kN
d. 6706.59 kN
a. 4698.00 kN
C. 4610.78 kN
16. Compute for the safe load that
could be carried by the tension
member.
b. 4654.39 kN
d. 6706.59 kN
a. 4698.00 kN
C. 4610.78 kN
Transcribed Image Text:SITUATION III: The cross section of a tension member is shown below: Use Fy=275 MPa, Fu=400 MPa. 25 350 16 mm O 30 25 350 12. Compute for the gross area of the cross section. a. 28 000 mm² C. 23 490 mm? b. 29750 mm² d. 23000 mm? 13. Compute for the allowable tensile capacity due to yielding. a. 4698.00 kN b. 4654.39 kN - C. 4610.78 kN d. 6706.59 kN 14. Compute for effective net area if shear lag factor is 0.90. Diameter of holes is 3mm more than that of bolts. a. 28 000 mm? C. 23 490 mm? b. 29750 mm? d. 23000 mm? 15. Compute for the allowable tensile capacity due to rupture. b. 4654.39 kN d. 6706.59 kN a. 4698.00 kN C. 4610.78 kN 16. Compute for the safe load that could be carried by the tension member. b. 4654.39 kN d. 6706.59 kN a. 4698.00 kN C. 4610.78 kN
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