Situation 2.A W14x90 of A992 steel is used as a pin-connected column. The 30ft long column is braced atmid-height with respect to its weak axis. Determine the axial compressive load. (ASD & LRFD)30ftProperties of W14x90:15ft15ftA = 26.5 in.²d = 14.0 in.by= 14.5 in.t₁ = 0.710 in.tw = 0.440 in.Tx = 6.14 in.ry = 3.70 in.by/2t, = 10.2h/tw = 25.9

The cutback width appears to be half of an unknown value, but the full value is not labelled in the…

Answered: Situation 2. A W14x90 of A992 steel is…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A W610 x 82 beam of A 36 steel has end reaction of 302 kN and is supported on a plate with a length of bearing of 139 mm. Fy = 248 MPa. Properties: d = 599 mm tw = 11 mm tf = 12.8 mm K = 33.76 Determine the compressive stress at the toe of the fillet (web yielding) for end reaction.
... Determine the nominal axial compressive strength, Pn for the following cases: a. L= 15 ft b. L = 20 ft Note: Pinned both end support W10 × 33 A992 steel r = 1.94 in E = 29000 ksi Fy = 50ksi L a) Blank 1 b) Blank 2 Blank 1 Add your answer Blank 2 Add your answer
PERFORMED AS REQUIRED. SHOW YOUR COMPLETE SOLUTION. 4.3-1 Use AISC Equation E3-2 or E3-3 and determine the nominal axial compressive strength for the following cases: a. L = 10 ft b. L=30 ft L W10 x 100 A992 steel FIGURE P4.3-1
Q2) The members of the truss structure shown below is plain concrete. The compressive strength of the concrete is 25 MPa. Compute the maximum load P that can be carried by the structure. (Cross section of each member of the truss is 200 x 200 mm and don't use material factors and do not consider slenderness) Comment on your results briefly. P A& 2m SC 2 m 1380 2m D
2. The column shown in the figure is reinforced with 6 - 25mm diam steel with fy: = 415Mpa and f'c = 27Mpa a. Determine the nominal load pn when e = 200mm b. Determine the nominal load when e = 350mm C. 250 mm 65 mm 400mm 65 mm e CD Pn
Write your answer (3 decimal places) on the text box provided in each number and use three (3) decimal places in all the computations. The compression member, 8 m long. loaded with service loads has braced in the weak direction as shown in the figure. A992 steel (EF 350 MPa and F.= 450 MPa) is used. Local stability is not a requirement. Use ASD.\ POL= PLL-160OKN 800 KN 4.30m W-shape 3.70m POL 800 KN PLL=1600KN 1. If a W16 x 77 is used, what is the value of the slenderness ratio to be used in this compression member?0 2. Compute the allowable compressive strength of a W 16 x 77 if used for this column in KN.O 3. Select the lightest W shape for the compression member.0 4. What is the value of the slenderness ratio used for the lightest W shape?0
The given frame is unbraced, and bending is about the x axis of each member. The axial service loads are: DL= 908 KN and LL= 1816 KN. E= 350 MPa. Use LRFD. a). Determine Kx for member AB. Use the stiffness reduction factor if possible. b). Determine the axial compressive design strength of column AB. 7.60 m W18 × 50 Am WI8 x50 B 4m WI8× 97 26X81M
2. Determine whether the compression member shown in Figure P4.3-7 is adequate to support the given service loads. a. Use LRFD. b. Use ASD. D = 560 kips L = 68 kips W12 × 79 A992 steel 20'
Situation 3. A W12x81 is used as a column. The effective length in either principal direction is 20ft. Using A992 steel, determine the axial compressive strength (ASD & LRFD). Properties of WT12x81: A = 23.9 in.² d = 12.5 in. by - 13.0 in. t = 1.22 in. tw = 0.705 in. 1x == 3.50 in. ry = 3.05 in. by/2t, = 5.31 d/tw = 17.7 y = 2.70 in. Ix = 293 in.* ly = 221 in. J = 9.22 in.
2. The beam shown in Figure P5.8-3 is a W16 × 31 of A992 steel and has continuous lateral support. The two concentrated loads are service live loads. Neglect the weight of the beam and determine whether the beam is adequate for flexure and shear. a. Use LRFD. b. Use ASD.
A column is built up from four (4)- 125 x 125 x 18 angle shapes as shown. The plates are not continuous but are spaced at intervals along the column length and function to maintain the separation of the angles. They do not contribute to the cross-sectional properties. The effective length is 4 m. Compute the allowable design compressive strength based on flexural buckling. E= 250 MPa. Use ASD. k 375 mm 125mm, HPlate 125mm 4 - 4 125 × 125× l8 section 下好业

Determine the nominal axial compressive strength, Pn for the following cases: a. L = 15 ft b. L = 20 ft Note: Pinned both end support W10× 33 r = 1.94 in E = 29000 ksi Fy = 50ksi A992 steel %3D Note: Ag = 9.71 in^2 a) Blank 1 b) Blank 2 Blank 1 Add your answer Blank 2 Add your answer

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