See the following table of concentration, green intensity, blank. Based on these data, convert intensity data into absorbance. Make a plot ofabsorbance versus relative concentration. Find the equation for the best fit line on the plot.Concentration (M)Green intensity (I)Blank (lo)Absorbance (-log 1/10)0.0002342340.1002282340.2002212340.3002162340.4002112340.5002032340.6001992340.7001912340.8001852340.9001792341.000174234a) Show the best fit line as the form of y = ax + b for your answer. You do not need to show your plot. How much is the slope (m) in this best fit line asthe form of y = mx + b in your answer?Type your answer... a) Let's assume that the best fit line is the form of y = 0.2291x-0.01310 for your result.b) If you have the absorbance of 0.0469 for the unknown solution, what could be the concentration (M) of this unknown solution? You should putyour answer as a decimal form. Do not forget the proper number of significant figures.Type your answer...

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Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions

Section: Chapter Questions

Problem 77PS

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.Q1. To determine the concentrations (mol/L) of Co(NO3)2 (A) and Cr(NO3)3(B) in an unknown sample, the following representative absorbance data wereobtained.A (mol/L) B (mol/L) 510nm 575nm5×10−1 0 0.714 0.0970 6×10−2 0.298 0.757Unknown Unknown 0.671 0.330Measurements were made in 1.0 cm glass cells.i. Calculate the four molar absorptivities: ∈A(510), ∈A(575), ∈B(510) and ∈B(575).ii. Calculate the molarities of the two salts A and B in the unknown.
Given the following sample concentrations and corresponding absorbances, construct a standard curve of absorbance vs. concentration and determine the molar absorptivity constant. Sample Concentration 15 μΜ 25 μΜ 40 μΜ Absorbance 0.19 0.32 0.49 55 μΜ 0.70
Unrounded Rounded ε∗,L/μmol 0.0259825 0.0260 Heres the data if needed: TZ # Concentration Absorbance at 430 nmnm 1 33.6480 0.931 2 25.2360 0.757 3 16.8420 0.210 4 8.41200 0.137 5 4.20600 0.122
A standard curve of absorbance vs. concentration has a linear trendline of y = 0.56x + 0.987. Use this trendline to calculate the concentration of an unknown sample that has an absorbance of 1.245.
Briefly describe how a phase-contrast microscope work and the kind of image that itproduces. Give a specific use for this type of microscope.
Blue Blue dye stock solution Absorbance at 630 nm Calibration curve Part 1: 0.1944 M 0.00697 y = 0.0682x A purple solution is prepared by mixing 5.00 mL of the blue dye solution with 6.75 mL of red dye solution. The calibration curve for each color is provided. Part 2 out of 3 (a) Determine the theoretical molar concentration of each dye in the mixture. [Blueltheoretical = 8.27 x 10-2 [Red] theoretical = 1.16 [Bluelexperimental [Redlexperimental " *10-1 M M x 10 (b) Using the absorbance and calibration curve for each dye, calculate the experimental molar concentration of each dye in the mixture. x 10 Red Red dye stock solution Absorbance at 500 nm Calibration curve 0.2015 M 0.00193 y = 0.0170x M M
Which data point in your standard curve is the most important in determining the best straight line 1. through your data? Why? Which is the second most important? Why? pathlength cell displays % T of 50.0 what is the Absorbance of the solution and what is the absorptivity (in /cm-mole). What Absorbance would be expected for a 5.0 x 10-6 M solution? What % T would this correspond to? 2. A solution of a light absorbing species with a concentration of 1.0 x 10-5M in a 1.0 cm
You are measuring the concentration of an unknown protein sample, and the absorbance at 595 nm (or A595) of your unknown is greater than that of the highest-concentration standard solution. It is not advisable to simply extrapolate the line of the standard curve to calculate the concentration of the unknown In this scenario, what would be the best strategy to measure the concentration of your unknown (instead of extrapolating from the standard curve)? (answer in 5 sentences)
You are measuring the concentration of an unknown protein sample, and the absorbance at 595 nm (or A595) of your unknown is greater than that of the highest-concentration standard solution. It is not advisable to simply extrapolate the line of the standard curve to calculate the concentration of the unknown In this scenario, what would be the best strategy to measure the concentration of your unknown (instead of extrapolating from the standard curve)?
What is the linearity (r2) value of the following concentration and absorbance values: SAMPLE CONCENTRATION ABSORBANCE 1 0.178 0.2127 2 0.274 0.2715 3 0.473 0.3892 4 0.574 0.4568 5 0.673 0.5327 6 0.864 0.6283 0.9786 0.9876 0.9562 0.9976
3. If you wished to study the molecule below by measuring absorbance, what wavelength should you set your spectrophotometer to? 1.6 Absorbance 1.4 1.2 1.0 0.8 0.6 0.4- 0.2- ME 0.0 300 400 600 Wavelength (nm) 500 Solutions and Mol....pdf 2 700 20221027_141317.jpg 800
The extinction coefficient for FD&C Blue Dye #1 is 138,500 cm-L/mol at 630 nm. A chemist collected the following data at 630 nm. She also found that the absorbance of an FD&C Blue Dye #1 solution of unknown concentration was 0.565. Use your graphing calculator to generate a standard curve from this data set, and use it to determine the concentration of the unknown solution. Concentration of Blue Dye (M) 6.35x10-7 1.23x10-6 3.84x10-6 5.68x10-6 Absorbance @ 630 nm 0.088 0.160 0.541 0.787

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