Second base A G UUU UCU Phe UCC UAU UGU Tyr Cys UUC UAC Ser UAA Stop UGA Stop A UGC UUA Leu UUG UCA UCG UAG Stop UGG Trp G CGU His CUU CCU CAU CUC Leu CUA CAC Pro CCA CCC CGC Arg CGA CAA Gln CAG CUG CCG CGG AAU AGU Asn Ser AGC AUU ACU AUC Ile ACC Thr AAC AUA AGA Lys Arg AGG ACA AAA AUG Met ACG AAG GAU GGU Asp GGC Gly GGA GUU GCU GUC Val GUA GAC Ala GCC G GCA GAA Glu GAG GUG GCG GGG G 15.10 The genetic code consists of 64 codons. First base Third base
Second base A G UUU UCU Phe UCC UAU UGU Tyr Cys UUC UAC Ser UAA Stop UGA Stop A UGC UUA Leu UUG UCA UCG UAG Stop UGG Trp G CGU His CUU CCU CAU CUC Leu CUA CAC Pro CCA CCC CGC Arg CGA CAA Gln CAG CUG CCG CGG AAU AGU Asn Ser AGC AUU ACU AUC Ile ACC Thr AAC AUA AGA Lys Arg AGG ACA AAA AUG Met ACG AAG GAU GGU Asp GGC Gly GGA GUU GCU GUC Val GUA GAC Ala GCC G GCA GAA Glu GAG GUG GCG GGG G 15.10 The genetic code consists of 64 codons. First base Third base
Chapter4: Management Practices For Finfish
Section: Chapter Questions
Problem 23SA
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Question
Referring to the genetic code presented in Figure , give the amino
acids specified by the following bacterial mRNA sequences.
Q. 5′ –AUGUUUAAAUUUAAAUUUUGA–3′
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