Right now I am in the beautiful city of Vancouver, Canada but can't enjoy my time here since I have to put the homework online for you to learn. There is a place called Grouse Mountain which has a very nice view of the whole city at night and a few good restaurants. There are a lot of tourists like myself. I would like to know what is the proportion of the tourists are from the USA? Suppose that I randomly ask n, 139 number of tourists whether they are from the USA and I got X 72 number of the people I asked are from the USA. What is the upper level (UL) of the 95% confidence interval that the proportion of all the tourists are from the USA? Tip: Using the template for interval estimation for the population proportion, enter the sample proportion as X/n, example: if n=150 and X = 130, X/n = 130/150 = 0.866666667 or 86.66667%, you enter 0.8667 (4 decimals in the template).
Right now I am in the beautiful city of Vancouver, Canada but can't enjoy my time here since I have to put the homework online for you to learn. There is a place called Grouse Mountain which has a very nice view of the whole city at night and a few good restaurants. There are a lot of tourists like myself. I would like to know what is the proportion of the tourists are from the USA?
Suppose that I randomly ask n, 139 number of tourists whether they are from the USA and I got X 72 number of the people I asked are from the USA.
What is the upper level (UL) of the 95% confidence interval that the proportion of all the tourists are from the USA?
Tip: Using the template for
Write with 4 decimals, for example, if it is 64.334%, write: 0.6433.
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