Question: Chip sequences for each node given as: user1 => c1 = [+1 +1 +1 +1] user 2 => c2 =[+1 -1 +1 -1] user 3 => c3 = [+1 +1 -1-1] user 4 => c4 = [+1 -1 -1 +1] Data bit for each user given as => user1: d1 = 0, user2: d2 = 0, user3: d3 = silent, user4 d4 = 1 Assumption: Data representation in CDMA: Data bit 0 -> -1, Data bit 1 -> +1, Silence (No data) -> 0 Which of the answer below shows common channel data (that contains all four signals)? A. +1 +1 +3 -1 B. -1-1-3+1 C. [-1-1+3+1]

Introductory Circuit Analysis (13th Edition)
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Review: Code division multiple access (CDMA) belongs to the family of channel partitioning protocols. It
is prevalent in wireless LAN and cellular technologies. In CDMA, one channel carries all transmissions
simultaneously. Multiple simultaneous transmission is separated using code theory.
1
d₁.c₁
d3 C3
3
Question:
A. +1 +1 +3 -1
B. -1-1-3 +1
d₁ C₁ + d₂. C₂ + d3 C3 + d4.c4
Data
C. [-1-1 +3 +1]
D. Error!
Simple idea of communication with code
2
d₂
4
d₂ C2
Common
channel
Chip sequences for each node given as:
user1 => c1 = [+1 +1 +1 +1]
user 2 => c2 =[+1 -1 +1 -1]
user 3 => c3 = [+1 +1 -1-1]
user 4 => c4 = [+1 -1 -1 +1]
Data bit for each user given as => user1: d1 = 0, user2: d2 = 0, user3: d3= silent, user4 d4 = 1
Assumption: Data representation in CDMA: Data bit 0 -> -1, Data bit 1 -> +1, Silence (No data) -> 0
Which of the answer below shows common channel data (that contains all four signals)?
d4 C4
Transcribed Image Text:Review: Code division multiple access (CDMA) belongs to the family of channel partitioning protocols. It is prevalent in wireless LAN and cellular technologies. In CDMA, one channel carries all transmissions simultaneously. Multiple simultaneous transmission is separated using code theory. 1 d₁.c₁ d3 C3 3 Question: A. +1 +1 +3 -1 B. -1-1-3 +1 d₁ C₁ + d₂. C₂ + d3 C3 + d4.c4 Data C. [-1-1 +3 +1] D. Error! Simple idea of communication with code 2 d₂ 4 d₂ C2 Common channel Chip sequences for each node given as: user1 => c1 = [+1 +1 +1 +1] user 2 => c2 =[+1 -1 +1 -1] user 3 => c3 = [+1 +1 -1-1] user 4 => c4 = [+1 -1 -1 +1] Data bit for each user given as => user1: d1 = 0, user2: d2 = 0, user3: d3= silent, user4 d4 = 1 Assumption: Data representation in CDMA: Data bit 0 -> -1, Data bit 1 -> +1, Silence (No data) -> 0 Which of the answer below shows common channel data (that contains all four signals)? d4 C4
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