Question 9: Suppose that the alkene in Figure 9 reacts with 1 mole of hydrogen chloride. Predict the structure of the main product of the reaction. [Generate a SMILES notation: https://jsme-editor.github.io/dist/JSME test.html. Copy the notation (CTRL+C) and paste it as the answer to this question (CTRL+V).] * Jou antwoord Figure 9

Question 9: Suppose that the alkene in Figure 9 reacts with 1 mole of hydrogen chloride. Predict the structure of the main product of the reaction. [Generate a SMILES notation: https://jsme-editor.github.io/dist/JSME test.html. Copy the notation (CTRL+C) and paste it as the answer to this question (CTRL+V).] * Jou antwoord Figure 9

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter1: Basic Concepts Of Chemistry

Section: Chapter Questions

Problem 61RGQ: Copper: (a) Suppose you have a cube of copper metal that is 0.236 cm on a side with a mass of 0.1206...

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Copper: (a) Suppose you have a cube of copper metal that is 0.236 cm on a side with a mass of 0.1206 g. If you know that each copper atom (radius = 128 pm) has a mass of 1.055 1022 g (you will learn in Chapter 2 how to find the mass of one atom), how many atoms are there in this cube? What fraction of the cube is filled with atoms? (Or conversely, how much of the lattice is empty space?) Why is there empty space in the lattice? (b) Now look at the smallest, repeating unit of the crystal lattice of copper. Knowing that an edge of this cube is 361.47 pm and the density of copper is 8.960 g/cm3, calculate the number of copper atoms in this smallest, repeating unit.
The symbol (Kr] represents O 4s²4pº. O 1s22s22p63s23p63d104s24p64d10 O 1522s22p63s23p64s²4p6. O1s22s22p63s23p63d104s²4p6 N
I3D 23 yands 378 g f) 3.8 x 10 mol x 0.0670 mol h) (2.3 x 10 m) (4.567 x 10° m)= 2.3x100m 4.
2p 25 15 30 17 30% 10 201 20 10 10g Q2/ Complete the following diagram for the carbon molecule (C2): 2p 2s 1s
التاريخ How manymolesetcoRferafe in 6,000r000atome of Copper
Third Math X Microsoft T x Microsoft Te x DOCX File v X 4. Personal - → C A app.edulastic.com/student/assessment/60525b29af74cf0008c2b68f/class E- > NEXT Question 17/19 A BOOKMARK 17 Use the image of a partial periodic table to answer questions 17, 18 and 19. 18 2 Не H. 1 Hyder 2 Hellum 4.00 101 13 14 15 16 17 4. 6. C 8 10 Ne 2. Li Be B N F Lthum 694 Berylum Borge Carton 10.81 1 12.01 Devgen 16.00 Puine Neon 20.18 9.01 14.01 19.00 11 12 13 14 15 16 17 18 Ar Na Mg sum 24.31 Al CI 3. Sodum 22.99 Si See 26.09 Aumin Argon 39.95 Cherine 3. 30.97 26.98 32.06 15 45 19 K 31 20 21 32 Ge 33 As 34 Ca Sc 35 Br 36 Kr Ga Caum 69.72 Se ... Protacsum 39. 10 Caldum 40.08 Arsenir Sele Bromine 44.96 72.63 74.92 78.97 79 90 3.80 38 37 Rb 39 Y. 49 50 Sn 51 Sb 52 53 54 Sr In Te Xe ... Srentium erum due 114.82 emony Taluum Jodine 5.47 87.62 118.71 121.76 127.60 126.90 131.29 Which elements have more protons per atom than phosphorus? bromine and sulfur B helium and nitrogen nitrogen and sodium sodium and…
student found a bottle of unknown origin in the basement of an "CAUTION—contains С₁H₁O.” No other A old house. The bottle was labelled information was given, but inside the bottle were some white crystals. The student took the bottle to a chemistry laboratory, where she analyzed the crystals with the help of the laboratory staff. C₁2H₁6O reacted with Br₂ in CCl4 adding one mole of Br, and forming C₁₂H₁OB2₂. When a sample of C₁₂H₂O was reacted with O3 followed by Zn/H₂O, two different samples, J and K, were obtained. Compound J had a molecular formula of C.HgO₂, and its NMR is shown below. Compound K had a molecular formula of C₂H₂O, and it could be oxidized to compound L, with a molecular formula of C₂H₂O₂. The IR spectrum of L showed a very wide, strong band centred around 3000 cm*¹. The NMR spectrum of L showed only two different absorptions: a doublet (6H) at 0.9 ppm and a septet (1H) at 3.6 ppm. There was also a singlet (1H) off the scale at 11.8 ppm. students, deduce possible…
Part C Ph-C-Ph+ PHNHNH₂ Draw the molecule on the canvas by choosing buttons from the Tools (for bonds- DOC I Z H A L CH 2D EXP. CONT? L 1 एल Marvin JS 31
Complete the following chart by writing "LEFT", "RIGHT" OR "NONE" for equilibrium shift, and "INCREASES", "DECREASES" or "REMAINS THE SAME" for the concentrations of reactants and products when the indicated stressors are applied to the given system at equilibrium. 2 SO₂ (8) + O₂(g) ↔ 2 SO 3 (8) SISSA OOON NR E O > SON MA Equilibrium Shift Concentration of SO2 Concentration of 02 Concentration of SO3
2. C12H24(I) + O2(g)
M|OM|O G fil app.101edu.co Maps ouTube F1 80 F3 E D C $ 4 c|o X G d Question 23 of 31 The molecules shown below are Aa F4 R F P₂ % 5 V A F5 T G В B 8 6 MacBook Air F6 B Y H 7 F7 с N 2|GT|G B * 8 J 기 A) Identical molecules B) Stereoisomers C) Constitutional isomers D) Isotopes E) Neither identical nor a type of isomer Done F8 B M W ( 9 G 17 CS UO N E E K F9 O H L F10 U P B > F11 Gra الہا + 11 ☐ ? X command option F13 1
other է HIO4 0 KMnO4 SHO + Na2Cr2O7 HO HO DMP P PCC OL