Question 9 of 16 (a) Number 3.12 (b) Number At the instant the displacement of a 2.00 kg object relative to the origin is a = (2.00 m) î+ (4.00 m) Ĵ - (3.00 m) k, its velocity is = -(8.82 m/s) î+ (5.79 m/s) ĵ + (4.16 m/s) k and it is subject to a force = (6.23 N) -(6.09 N) ĵ + (4.94 N) k. Find the acceleration of the object ((a), (b) and (c) for î, and components respectively), the angular momentum of the object about the origin ((d), (e) and (f) for î, and components respectively), the torque about the origin acting on the object ((g), (h) and (i) for î, ĵ and ✩ components respectively), and (j) the angle between the velocity of the object and the force acting on the object. (c) Number 2.47 -3.05 (e) Number (d) Number i 43.7 (f) Number < i > Units Units Units Units m/s^2 Units m/s^2 Units m/s^2 0.3 / 1 E

Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
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Chapter6: Motion In Two Dimensions
Section6.3: Relative Velocity
Problem 27PP
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Question 9 of 16
(a) Number 3.12
(b) Number -3.05
At the instant the displacement of a 2.00 kg object relative to the origin is
a = (2.00 m) î+ (4.00 m) - (3.00 m) , its velocity is
= -(8.82 m/s) î+ (5.79 m/s) ĵ + (4.16 m/s) k and it is subject to a force = (6.23 N) î - (6.09 N) Ĵ + (4.94 N) Â. Find the acceleration
of the object ((a), (b) and (c) for î, j and k components respectively), the angular momentum of the object about the origin ((d), (e) and
(f) for î, and components respectively), the torque about the origin acting on the object ((g), (h) and (i) for î, and components
k
respectively), and (j) the angle between the velocity of the object and the force acting on the object.
(c) Number 2.47
(d) Number i 43.7
(e) Number i
<
(f) Number
i
>
Units
Units
Units
Units m/s^2
Units
m/s^2
Units
m/s^2
0.3 / 1
Transcribed Image Text:Question 9 of 16 (a) Number 3.12 (b) Number -3.05 At the instant the displacement of a 2.00 kg object relative to the origin is a = (2.00 m) î+ (4.00 m) - (3.00 m) , its velocity is = -(8.82 m/s) î+ (5.79 m/s) ĵ + (4.16 m/s) k and it is subject to a force = (6.23 N) î - (6.09 N) Ĵ + (4.94 N) Â. Find the acceleration of the object ((a), (b) and (c) for î, j and k components respectively), the angular momentum of the object about the origin ((d), (e) and (f) for î, and components respectively), the torque about the origin acting on the object ((g), (h) and (i) for î, and components k respectively), and (j) the angle between the velocity of the object and the force acting on the object. (c) Number 2.47 (d) Number i 43.7 (e) Number i < (f) Number i > Units Units Units Units m/s^2 Units m/s^2 Units m/s^2 0.3 / 1
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