QUESTION 8Consider the pathway for the synthesis of the amino acid arginine in Neurospora:ARG-E→ citrullineARG-FARG-Hornithineargininosuccinate arginineMutant strains of Neurospora may carry one or more mutations. Neurospora mutant strain b is grown on minimal media plus supplements as shown.Growth is shown by (+) and no growth is shown by (o).Supplementsornithinemutant nothingcitrullinearginino-succinateargininestrainWhat can you conclude from these data?O Strain a has only one mutation and it is in ARG-E.O Strain b has only one mutation and it is in ARG-H.O Strain a has a mutation in ARG-F and strain b has a mutation in ARG-E.O Strain b has mutations in ARG-E, ARG-F, and ARG-H.+ +

The mutation in a particular gene that produce an enzyme for a metabolic process will affect the…

QUESTION 8 Consider the pathway for the synthesis of the amino acid arginine in Neurospora: ARG-E ARG-F ARG-H ornithine citrulline - argininosuccinate arginine -> Mutant strains of Neurospora may carry one or more mutations. Neurospora mutant strain b is grown on minimal media plus supplements as shown. Growth is shown by (+) and no growth is shown by (0). Supplements ornithine nothing citrulline arginino- mutant arginine strain succinate a What can you conclude from these data? O Strain a has only one mutation and it is in ARG-E. O Strain b has only one mutation and it is in ARG-H O Strain a has a mutation in ARG-F and strain b has a mutation in ARG-E O Strain b has mutations in ARG-E, ARG-F, and ARG-H.

QUESTION 8 Consider the pathway for the synthesis of the amino acid arginine in Neurospora: ARG-E ARG-F ARG-H ornithine citrulline - argininosuccinate arginine -> Mutant strains of Neurospora may carry one or more mutations. Neurospora mutant strain b is grown on minimal media plus supplements as shown. Growth is shown by (+) and no growth is shown by (0). Supplements ornithine nothing citrulline arginino- mutant arginine strain succinate a What can you conclude from these data? O Strain a has only one mutation and it is in ARG-E. O Strain b has only one mutation and it is in ARG-H O Strain a has a mutation in ARG-F and strain b has a mutation in ARG-E O Strain b has mutations in ARG-E, ARG-F, and ARG-H.

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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Question 4 a-D-galactose from B-D-glucose can be differentiated using which method of analysis? All of these Methylation analysis O Use of exoglycosidases NMR by the change in chemical shift
QUESTION 6 A series of experiments were performed in Neurospora crassa in order to define the tryptophan biosynthesis pathway. In one of these experiments, five tryptophan auxotrophs were isolated and tested for growth on tryptophan and five other known intermediates in the tryptophan biosynthesis pathway. The growth responses are shown below: Growth on Anthranilic Acid (AA) Growth on Indole Growth on Indole Glycerol Phosphate (IGP) Growth on Chorismic Acid (CA) Growth on N- Anthranilate (NA) Growth on Tryptophan Mutants: trp-1 trp-2 + + trp-3 + trp-4 + + + trp-5 + + + - + + + + + + Using the growth data in the above table, indicate the precursor (molecule that you start with) and the order of the intermediates in this pathway (please use exact spelling or abbreviation). Rxnl Rxn2 Rxn3 Rxn5 Tryptophan Rxn4 Indicate the mutant that is associated with the enzyme that catalyzes the reactions for tryptophan biosynthesis using the data given in the above table. Rxn1: Rxn2: Rxn3: Rxn4: Rxn5:
QUESTION 12 The leucine zipper domain of transcription factors is not involved in DNA recognition but rather in facilitating dimerization. Given the chemical properties of the amino acid leucine, dimerization of transcription factors via this domain by (select the correct option). Facilitating hydrogen bonding with the aqueous environment. Chelation of bivalent ions such as Zn2+. Formation of coiled-coils through hydrophobic non-covalent interactions between evenly spaced Leu residues in alpha-helical domains. Physically connecting the two transcription factor subunits through unstructured loops.
Question 1 options: The specificity pocket of the serine protease chymotrypsin, which interacts with Tyr and Phe-containing peptide sequences, contains a Ser residue. A research group is trying to modify chymotrypsin such that it has a low KM with Trp-containing peptides. Enter the name or abbreviation of an amino acid that the Ser could be mutated to that would likely have the desired effect. (Hint: look at the diagrams of the specificity pockets shown in the course slides, and consider how the Ser would need to change to account for the difference between Tyr/Phe and Trp.)
Question 20 The "single promoter" hypothesis for transcription of minus-sense ssRNA viruses was best supported by: The effect of alpha-amanatin on transcription of the genome, The ability to replicate in human and insect cells. O The presence of small, sub-genomic antisense RNAS. O The UV-target sensitivity of transcripts is greater than their coding size the further from the 3-end you go
Question 6A You gather the following data on the expression of a eukaryotic gene which experiences positive gene regulation (induction). What the gene product is or how it is induced is not important for understanding the problem. The numbers indicate the amounts of product seen at each stage listed (what the units are isn't important either). At what stage of the gene expression process is the production of the gene's protein being affected? What data leads you to think this? Remember, this is a eukaryote. Induced Uninduced Transcription initiation 100 4 Poly-A pre-MRNA 95 Spliced mRNA 93 MRNA in the cytosol (t=0) 92 4 MRNA in the cytosol (t=60 85 min) Total protein product 300 1 (t=60 min)
QUESTION 23 The pl of hen lysozyme is 11.0; the pl of hen ovalbumin is 4.6. An isoelectric focussing experiment is conducted. Which of these two proteins will migrate closest to the negative pole? hen lysozyme Both proteins will remain at the origin Hen ovalbumin
Question 9 The mechanism for all template-directed synthesis of any type of nucleic acid involves which of the following? A nucleophilic attack of a 3' hydroxyl toward a phosphoryl group of a nucleoside triphosphate, releasing PPi. B nucleophilic attack of a 5' hydroxyl toward a phosphoryl group of a nucleoside triphosphate, releasing PPi. nucleophilic attack of a 5' hydroxyl toward a phosphoryl group of a nucleoside triphosphate, releasing PPi. D nucleophilic attack of a 3' hydroxyl toward a phosphoryl group of a nucleoside monophosphate, releasing Pi.
QUESTION 7 You are trying to use qPCR to compare gene expression of nitrous oxide reductase (nosZ) in a Pseudomonas sample treated under various conditions. Using the 2-delta deltact method, about how much higher (or lower) is the expression of nitrous oxide reductase (nosZ) in the experimentally treated sample verses the untreated sample? nosZ Ct values for untreated sample (control conditions) Internal housekeeping nosz Ct values for Internal housekeeping gene Ct values for untreated sample (control conditions) gene Ct values for treatment sample experimental treatment sample experimental Replicate 1 21.3 20.0 19.8 20.9 Replicate 2 21.5 20.1 19.7 21.0 Replicate 3 21.4 20.3 19.5 20.7 Replicate 4 21.6 20.2 19.4 21.1 O A. -2 times higher B. -100 times higher C. about 20% as much as the control O D.-3.5 times higher O E. -12 times higher O F. -6 times higher than the control
Question 15 The higher protein abundance observed in the ACE20E allele compared to the wild- type (ACE2*) allele is caused by altered regulation of gene expression at the post- transcriptionalL level. Which of the following mechanisms are a likely explanation for the abnormally high protein expression from the ACE20E allele? Select all that apply C Increased length of the poly-A tail increases mRNA stability and translational efficiency Alternative splicing makes a shorter protein that is translated faster Faster 5' capping increases MRNA stability and translational efficiency Decreased microRNA expression reduces translational inhibition and ACE2 MRNA degradation All of the above mechanisms are likely explanations
QUESTION 11 If the DNA gene is TAC GGT TTA CAG, which amino acids will be put together? O A. methionine-proline-aspargine-valine O B. tyrosine-glycine-leucine-glutamine OC valine-serine-threonine-lysine O D. phenylalanine-cysteine-tryptophan-alanine
Question 11 Given this MRNA strand: 3' - AUGAGGAAGGUA - 5'; what are the components of the polypeptide? First Position Third Position (3' end) (5' end) U A G UGU Cys UUU Phe UUC Phe UCU Ser UCC Ser UCA Ser UAU Tyr UAC Tyr UAA Stop UAG Stop |U UGC Cys UUA Leu UUG Leu UGA Stop |A UGG Trp U G CGU Arg CGC Arg CGA Arg UCG Ser CAU His САС His CAA Gln CAG Gln CUU Leu CCU Pro U ССС Pro CỤC Leu CỦA Leu CUG Leu CCA Pro A CCG Pro CGG Arg G U AAU Asn AAC Asn AAA Lys AAG Lys GAU Asp GAC Asp GAA Glu GAG Glu AUU Ile ACU Thr АСС Thr ACA Thr ACG Thr AGU Ser AUC Ile A AUA Ile AGC Ser AGA Arg A AUG Met* AGG Arg G GUU Val GGU Gly GCU Ala GCC Ala GCA Ala GCG Ala U GGC Gly GÚC Val G GUA Val GGA Gly |A GUG Val GGG Gly G