QUESTION 7 The results of an empirical study reveal the following: n=27, sample mean = 3,000, sample standard deviation = 900. The 90% confidence interval of the true population mean is closet to: 2,400 and 3,400 O 1,200 and 4,800 O 2,700 and 3,300 2,000 and 4,000 QUESTION 8 An analyst studied the average savings of recent college graduates. The results of the study reveal the following: n=40, sample mean = $16,000, sample standard deviation = $5,000. The probability that a randomly selected recent graduate has savings of $18,000 or more is closet to Hint: You need to calculate a z-score and remember to use the standard error in your calculations O more than 5% O less than 1%

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 14PPS
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QUESTION 7
The results of an empirical study reveal the following:
n=27, sample mean = 3,000, sample standard deviation = 900. The 90% confidence interval of the true population mean is closet to:
%3D
2,400 and 3,400
1,200 and 4,800
2,700 and 3,300
2,000 and 4,000
QUESTION 8
An analyst studied the average savings of recent college graduates. The results of the study reveal the following:
n=40, sample mean =
$16,000, sample standard deviation = $5,000.
The probability that a randomly selected recent graduate has savings of $18,000 or more is closet to
Hint: You need to calculate a z-score and remember to use the standard error in your calculations
more than 5%
less than 1%
about 95%
about 68%
Transcribed Image Text:QUESTION 7 The results of an empirical study reveal the following: n=27, sample mean = 3,000, sample standard deviation = 900. The 90% confidence interval of the true population mean is closet to: %3D 2,400 and 3,400 1,200 and 4,800 2,700 and 3,300 2,000 and 4,000 QUESTION 8 An analyst studied the average savings of recent college graduates. The results of the study reveal the following: n=40, sample mean = $16,000, sample standard deviation = $5,000. The probability that a randomly selected recent graduate has savings of $18,000 or more is closet to Hint: You need to calculate a z-score and remember to use the standard error in your calculations more than 5% less than 1% about 95% about 68%
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