QUESTION 5 Column Design: Given: a solid circular column carrying a compressive load of 8500 lb with pinned ends. The length is 50 in. Use SAE 4140 OQT 1000 steel and a design factor of 3.0. a) Sy for the material given above is_____ ksi
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- Column Design: Given: a solid circular column carrying a compressive load of 8500 lb with pinned ends. The length is 50 in. Use SAE 4140 OQT 1000 steel and a design factor of 3.0. a) Sy for the material given above is _____ ksi(1) Given A992 steel Ag = 10 in %3D KLy- 80, ry what is $ Pa=? = 60 the' column streugth designA W6 x 15 structural steel column is 24 ft tall and is fixed at its base and top. It is braced (horizontally) at the midspan. These braces are pin-connected to the column's web. Determine the load that the column can support so that it does not buckle nor the material exceeds the yield stress. Use the undermentioned data: Q2 E = 29 (10)³ ksi Oy = 60 ksi %3D Ik = 29.1 in ly = 9.32 in (This question has no diagram)
- A W16X31 A992 steel is used as a beam. The beam has a continuous lateral support. The uniformly distributed load shown in the figure is a service load that consists of 50% dead load (included the beam weight) and 50% live load. Using LRFD, determine the following? Note: A992 STEEL Fy = 50 ksi Ag = 9.13 in^2 Zx = 54.0 in^3 a. Ultimate (Governing Load Combo) Maximum Negative Moment (at support) in kips-ft b. Ultimate (Governing Load Combo) Maximum Positive Moment (at midspan) in kips-ft c. The Flexural Capacity of the Beam in kips-ft d. Demand Capacity Ratio of Beam really need answer pleaseA E E E E X 1 E E - E E E GD 1 I 2 3 4 I 5 Condition #1: A structural support for a machine is subjected to a static compression load of 20 kN. The support is manufactured from a circular rod made from SAE 1040 Hot Rolled steel. Specify suitable diameter for the cross section of the rod based on the basic size. Steel data are available in Table A-10 from the textbook. A-10 Typical properties of carbon and alloy steels. Ultimate strength, s Yield strength, s, Percent Material SAE no. Condition ksi MPa ksi MPa elongation 1020 Annealed 57 65 393 448 517 43 296 36 1020 Hot rolled 48 331 36 1020 Cold drawn 75 64 441 20 1040 Annealed 75 517 51 352 30 1040 Hot rolled 90 621 60 414 25 1040 Cold drawn WQT 700 WQT 900 WOT I 100 WOT 1300 97 669 82 565 16 1040 127 118 876 93 641 621 19 1040 814 90 22 1040 107 738 80 552 24 1040 87 600 63 434 32 1080 Annealed 89 614 54 372 25 1O80 OQT 700 OQT 900 OQT 1100 OQT L00 189 1303 972 141 129 12 1080 179 1234 889 13 1080 145 1000 103 710 17 1080 117 807 70…Problem 1 A steel connecting rod with length of 6 meters and is to be subjected to a tensile load of 70 KN. A. What will be the diameter if the total elongation is not to exceed 4 mm. B. Choose a stainless-steel material based on yield strength and dead load.
- Rolled steel section ISWB 300 is used as a column of height 6 m, fixed at base and pinned at top. Find the permissible compressive load on the column using the table of permissible compressive stresses as given in the table below: Cross-section properties of ISWB 300 section are as follows: Area of cross-section = 6133 mm² Flange width= 200 mm 10 mm 7.4 mm 2 dac λ Osc Flange thickness Web thickness = 50 132 13 57 2 = slenderness ratio 60 122 = 1xx Lyy = = 70 112 98.216 x 106 mm4 9.9 x 106 mm4 80 101 90 100 90 80 140 150 160 170 180 51 45 41 37 33 ac = allowable compressive stress in MPa Use linear interpolation for intermediate values of λ. 110 72 190 30 120 64 200 28Q2 A W6 x 15 structural steel column is 24 ft tall and is fixed at its base and top. It is braced (horizontally) at the midspan. These braces are pin-connected to the column's web. Determine the load that the column can support so that it does not buckle nor the material exceeds the yield stress. Use the undermentioned data: = 29 (10) ksi Oy = 60 ksi I = 29.1 in %3D Iy = 9.32 inA column section is as shown in figure below. Z 320 mm- 20 mm Z ISMC 40 @ 49.4 kg/m The length of the column is 4.8 m. Using steel of grade Fe410, compute the design compressive load.
- A composite column member is fabricated on top of a base plate as shown in the figure. What should be the minimum safe thickness of the plate against punching if the total deformation of the column is 0.72 mm. Given below are the material properties. Material Jallowable Tallowable (MPa) (MPa) |(GPa) Steel 120 60 200 Aluminum 90 45 70 Steel (D- 55 mm Alurmmum (0-110 men) SteelInstruction: Answer the questions below: (CLO) A 20mm B Take E= 105 GN/m² 20mm C 20 kN A brass composite bar AB and BC in diameter 30mm and 15 mm respectively was installed rigidly as shown in figure below. Find the total elongation of the composite bar.A bronze bar is fastened between a steel bar and an aluminum bar as shown in the figure. Axial loads are applied at the positions indicated. The allowable overall deformation is not to exceed 1.2 mm. Assume that the 2P Aluminum L- 1.5 m A= 550 mm E= 70 GPa Steel Bronze L= 2.0 m L= 1.0 m A= 600 mm A= 650 mm E= 200 GPa E= 83 GPa assembly is suitably braced to prevent buckling. Find the maximum permissible value of P.