QUESTION 11 Of the following equilibria, only A) H2(g) + Cl2 (g) 2 HCl (g) B) 2 S03 (g) 2 SO2(g) + O2 (g) 2 NH3(g) 4 Fe (s) + 3 02 (g) C) N2 (g) + 3 H2 (g) D) 2 Fe203 (s) E) 2HI (g) OA OB. H2(g) + 12 (g) Cl2 (g) → 2 HCl (g) 2 502 (g) + 02 (g) B2 S03 (g) N2 (g) + 3 H2 (g) OD H2(g) + 2 Fe203 (s) 2 NH3 (g) 4 Fe (s) + 3 02 (g) + 12 (g) will shift to the right in response to a decrease in volume.

QUESTION 11 Of the following equilibria, only A) H2(g) + Cl2 (g) 2 HCl (g) B) 2 S03 (g) 2 SO2(g) + O2 (g) 2 NH3(g) 4 Fe (s) + 3 02 (g) C) N2 (g) + 3 H2 (g) D) 2 Fe203 (s) E) 2HI (g) OA OB. H2(g) + 12 (g) Cl2 (g) → 2 HCl (g) 2 502 (g) + 02 (g) B2 S03 (g) N2 (g) + 3 H2 (g) OD H2(g) + 2 Fe203 (s) 2 NH3 (g) 4 Fe (s) + 3 02 (g) + 12 (g) will shift to the right in response to a decrease in volume.

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 12.83PAE

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QUESTION 11 Of the following equilibria, only A) H2(g) + Cl2 (g) 2 HCl (g) B) 2 S03 (g) 2 S02 (g) + O2 (g) C) N2 (g) + 3 H2(g) 2 NH3 (g) D) 2 Fe203 (s) E) 2HI (g) OA OB. B2 S03 (g) OC H2(g) + OD 4 Fe (s) + 3 02 (g) H2(g) + 12 (g) N2 (g) + 3H2(g) O2 HI(g) Cl2 (g) 2 HCl (g) 2 SO2 (g) + 02 (g) 2 NH3 (g) 2 Fe203 (s) 4 Fe (s) + 3 02 (g) H2(g) + 12 (g) will shift to the right in response to a decrease in volume.
QUESTION 3 Of the following equilibria, only OA. () в. B2 S03 (g) H2 (g) + Cl2 (g) ⇒ 2 HCl (g) 2 SO2 (g) + O2 (g) ON2 (g) + 3 H2 (g) ⇒ 2 NH3 (g) 2 Fe203 (s) OD. OE 4 Fe (s) + 302 (g) 2H1 (g) → H2(g) + 12 (g) will shift to the left in response to a decrease in volume.
Question 32 of 45 View Policies Current Attempt in Progress Using the following equilibria and K. values: SO3(s) + NO(s) SO2(g) + NO2(g) 2 SO3ls) + N2(g)2 SO2(g) + 2 NO(g) the calculated value of K. for the reaction 2 NO2(g) + N2(g)54 NO(g) is K -5.0x 10 K -1.5 x 104 O 3.0x 1013 07.5x 104 06.0x 10-22 O 1.5x 10 11 Save for Later arch
Equilibrium Constant 82 4) ½N2(g) + 02(g)= NO2(g) Kc 1.04 x 10-9 N2(g) + 202(g) N204(g) Kc =7.42 x 10-18 %3D Calculate Kc for each of the following. (a) 2NO2(g) = N2(g) + 202(g) (b) N2(g) + 202(g) = N2O4(g) PA at O002 16 mnundiliupo 0002 10 eft 00. Cci boouho ss sllo eolom 02.1 bae chHto estom 021 H Tondiliupe is inso H lo esfomem won (c) 2NO2(g) = N2O4(g) a li nao adt ai ol borsluoleg uor asulev od of qued blooerW ( ort nadw M000,0 bau o oldeid 2aw bo ov suiev ol enos walha g0)dgid 2aw bo oy eulev TUwens uoy nislg M00.210 oulsDsd in la6
At 475 oC, Keq = 0.230 for the reaction: 1/3 NO2(g) + 1/3 N2O(g) (equilibrium arrows) NO(g) (a) What is the value of Keq for the reaction NO(g) 1/3 NO2(g) + 1/3 N2O(g)?Keq = .(b) What is the value of Keq for the reaction NO2(g) + N2O(g) 3 NO(g)?Keq = .(c) What is the value of Keq for the reaction 3 NO(g) NO2(g) + N2O(g)?Keq = .
How will a removing ammonia affect the following equilibria? N2(g) + 3H2(g) <=> 2NH3(g) ΔH= -92.2 kJ
QUESTION 5 Consider the following equilibrium expressions. A(g) + B(g): C(g) + D(g)- C(g) + D(g) E(g) + F(g) with equilibrium constant, K1 with equilibrium constant, K2 What is the equilibrium constant, K3, for A(g) + B(g) E(g) + F(g)? K2 K3 а. K1 b. · K3 = K1 – K2 K1 K3: K2 C. %3D d. K3 = K1 x K2 е. K3 = K1 + K2
Answer the remaining questions based on the equilibrium shown below at 973 K. Mo is the symbol for the element molybdenum. 2Mo(s) + CH4 (g)  Mo2C(s) + 2H2 (g) Kc =4.4×10–2 What is the value of Kc for the reaction: Mo2C (s) + 2 H2 (g)  2 Mo (s) + CH4 (g)? A) –4.4×10–2 B) 23 C) 4.4×10+2 D) 0.23 What is the value of Kc for the equilibrium: Mo (s) + 1⁄2 CH4 (g)  1⁄2 Mo2C (s) + H2 (g)? A) 0.21 B) 2.2×10–2 C) 1.9×10–3 D) 4.4×10–1
Consider the following equilibria: 2SO3(g) 2SO2(g) + O2(g) Kc1 = 2.3 × 10 – 7 2NO3(g) ⟷ 2NO2(g) + O2(g) Kc2 = 1.4 ×10 – 3 Calculate the equilibrium constant for the reaction: SO2(g) + NO3(g) ⟷ SO3(g) + NO2(g) A 1.3 × 10 – 2 B 1.6 × 10 – 4 C 78 D 6.1 × 103
2) For the hypothetical reactions 1 and 2, K₁= 10 and K₂ = 10. 2AB(g) 1. A2(g) + B₂(g) = 2. 2A2(g) + C₂(g) 3. A₂C(g) + B₂(g) What is the value for K for reaction 3? 2A₂C(g) 2AB(g) + (1/2)C₂(g)
3) Based on the information below, determine the value of the unknown equilibrium constant, Kc. 4 CO2 (g) + 2 H2O (g) « 4 O2 (g) + 2 CH2CO (g)Kc = 3.7 x 1017 CO2 (g) + 2 H2O (g) « CH4 (g) + 2 O2 (g)Kc = 8.3 x 10-15 CH4 (g) + CO2 (g) « CH2CO (g) + H2O (g)Kc = ?
6.) Given the following information: 2 A(g) + B(g) = A¿B(g) 2 A(g) + C2(g) = 2 AC(g) K1 = 5.0 x 104 K2 = 3.2 x 103 What is the net equilibrium constant (Knet) for the reaction? 2AC(g) + 4A(g)+ 3B(g)→ 3 A¿B(g) + C2(g)