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- Design a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A BC D) respectively with A is the MSB, the output variables are organized as (W X Y Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. X= BCD'+B'D+B'C X= BC'D'+B'D+BC X= BC'D'+B'D+B'C X= BC'D'+BD+B'CDesign a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A B C D) respectively with A is the MSB, the output variables are organized as (W XY Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. W=A+BD+BC' W=A+BD+BC, W=A'+BD+BC W= BC'D'+B'D+B'CConsider the following registers - AX contains 1122h, BX contains 3344h, CX contains 5566h and DX contains 7788h. ( You don't need to write code for this part) Write code to consolidate these value to two 32-bit registers - EAX and ECX. After executing your code, EAX should contain 11223344h and ECX should contain 77885566h. You are NOT allowed to mov any immediate values to the registers. h. Add a File Record Audio Listen
- The num ber -256can be represented usingwhich signed num ber representation method? a.7 bit 2s com plement b.9 bit unsigned birary c.8 bit one's com plement d.9 bit one's com plement e. None of the other choices.What will be the final value of DI after executing the following piece of code? Execute the instructions dependently one after another. CLD MOU CX,OFOH MOU AX,05678H MOU DI,01000H MOU ES, DI SUB DI, DI REPNZ SCASB -R AX-0000 DS-073F 073F:0100 0000 D 1000:0 F 1000:0000 92 00 14 12 54 56 44 78-AD 56 78 FO 00 00 00 00 BX-0000 CX-0000 DX-0000 SP-00FD ES-1000 SS%3073F CS=073F BP-0000 SI=0000 DI=0000 IP-0100 NU UP EI PL NZ NA PO NC ADD IBX SI1,AL DS:0000 CD TUDX.Ux..... .... Notes: 1- Use the DEBUG window to answer this question (values shown are prior to execution and in hexadecimal 2- Write down the final value of DI as four hexadecimal digits without any additional characters.The Xi and Yi given in the figure show the inputs of each Full Adders inside the parallel adder. Shows the Select end (S) and the Hand bit (Carry in- Cin) of the arithmetic circuit. Find the output F and the Cout value for the Select bit, Hand bit , A and B values given below. S=1, Cin=1 and A=(0111)2 , B=(0111)2
- ALP for 8-bit addition of numbers in register r2 and r3 and store result in register r5USE DIGITAL LOGIC AND DESIGN Part 1: In Figure_4; we have 4-bit Comparator using 2-bit Comparators block. You have to satisfy given condition by applying all data on figure 4. At the end, given condition should produce HIGH output and other two should be LOW. A3 A2 A1 A0 = 1101 and B3 B2 B1 B0 = 1110 Figure_4 Part 2: The serial data-input waveform (Data in) and data-select inputs (S0 and S1) are shown in Figure_5. Determine the data-output waveforms from D0 through D3. Figure_5 Part 3: Decoder can be useful when we have to decode some specific numbers from their equivalent code. Figure 6 has a concept of 3 to 8 line decoder from which you have to generate output waveform from D0 to D7 with proper relationship to input. Figure_6 Part 4: The data-input and…IC number for the X-OR gate is O a. 7486 O b. 7432 O c. 7400 O d. 7408 O e. 7404
- Explain the process of the following Load D3 · D3 12 12 D2 Do Clock D Load Block Diogram of 4-bit Reg with Paralel Lood - Do D >c Clock Logic Diogram of 4-bit Register with Paralel LoodA 32 bit comparator .... Please mark all answersthat are correct (at least one is correct).Is a combinational circuit ARequires only AND and OR gates to be implemented BIs a sequential circuit CCan be implemented using two 16-1 multiplexers DWith minor modifications can be transformed into a shift register E. solve this question in great detail explaining every single bit of info as i'm a complete beginner and i need to understand how to solve questions of this type. also provide small examples of how the solution would differ if the question was slightly alteredAdocs.google.com is a logic switch that select information from one of the input line and directs it to a single line Encoder Decoder Adder Multiplexer Binary to octal can be implemented used 3-8 De-Multiplexer Multiplexer Decoder Encoder System base 12 include numbers from ... to .... 1-B 1-C 1-12 1-11 ۹:۰۳ F