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- For a short period of time, a m = 3400 kg truck has a frictional driving force of FD = (650- +²) N acting on the wheels, where t is in seconds. At t = 0, the truck has a speed of of 01. m V₁ t = 0 V1 Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value 5 2/2 = 5.57 m S Using the Principle of Linear Impulse and Momentum, a. Determine the speed of the truck when t = 3 s, v2. Round your final answers to 3 significant digits/figures. X FD = f(t) m S V₂ t2For a short period of time, a m = 3400 kg truck has a frictional driving force of FD= (650- +²) N acting on the wheels, where t is in seconds. At t = 0, the truck has a speed of of v₁. V₁ t = 0 21 Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value m 5- s v2 = m Using the Principle of Linear Impulse and Momentum, a. Determine the speed of the truck when t = 3 s, v2. FD = f(t) Round your final answers to 3 significant digits/figures. m S V₂ t2A runner lands on her front foot with a force of 2043 N acting at 0 = 70 degrees to the horizontal. If the knee has a flexion angular velocity of 433 degrees/s. What is the power at the knee joint? Report to one decimal point. 0.3 m GRF 0.75 m 0.38 m
- = Q3. As shown on the right in image below, the force Facting on the box varies with displacement s, and the coefficient in the image, C = 18. Determine the work done by force F to the box when the box has displaced s 1.8 m. Please pay attention: the numbers may change since they are randomized. Negative sign must be included if the work done is negative. Your answer must include 2 places after the decimal point, and proper Sl unit. F Your Answer: Answer - S units F (N) C 1 2 s (m)Consider the following diagram. m1=20 kg and m2= 10 kg. The system is being pulled by an applied force of 200 N. directed 50" above the horizontal. The coefficient of kinetic friction between the block and the surface is u-0.2. 50 m, 20kg Coefficient of friction 4=0.2 10 kg. 309 7) Calculate the acceleration of the system. Your answer 8) Calculate the magnitude of the Tension on the rope. Your answer N 00A used battery was brought to the workshop and the technician noticed that it had 1 litre of distilled water in it but was fully discharged. The specs sheet for this type of battery states that it is fully charged when the change in distilled water to the change in charge equals to the difference between twice the amount of charge and the actual amount of distilled water existing in the battery For the used battery, derive the differential equation and state the initial condition for the range x= 0(0.2)1.0, then obtain a numerical solution for this equation using Euler’s method.
- A W = 58 lb block is pushed with a force that is defined by the equation F = (50+ s²) lb. The coefficient of kinetic friction of the block and surface is μ = 0.2. The spring is initially unstretched/uncompressed. s = 1 ft. F = f(s) k Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value lb ft 01 30 degrees Using equations of motion in rectangular coordinates and principle of work and energy, N (s) = P = 16 Vfinal = The block is initially at rest. At the instant, the block has moved a distance of a. Find an equation for the normal reaction between the block and surface as a function of s, N(s). b. Determine final velocity of the block, Vfinal. c. Determine the power developed by the force at the instant, P, in horsepower. m Round your final answers to 3 significant digits/figures. Round your coefficients in equations to 3 significant digits/figures. lb S hp k ft SWhen a 5000 lb car driven at 60 mph on a level road is suddenly put into neutral gear (i.e. allowed to coast), the velocity decreases in the following manner: 60 V = mph , 1+() where t is the time in sec. Find the horsepower required to drive this car at 30 mph on the same road. Useful constants: 9 = 22 mph/sec, 1 H.P. = 550 ft.lb/sec, 60 mph = 88 ft/sec.7. The arrangement in the drawing shows a block (mass = 14.0 kg) that is held in position on a frictionless incline by a cord (length = 0.582 m). The mass per unit length of the cord is 1.30 x 10-2 kg/m, so the mass of the cord is negligible compared to the mass of the block. The cord is being vibrated at a frequency of 166 Hz (vibration source not shown in the drawing). What is the smallest angle 0 between 15.0° and 90.0° at which a standing wave exists on the cord?
- Part A Consider the system in (Figure 1). Figure k = 5 lb/in. B y = x² 1 ft x 1 of 1 Determine the smallest amount the spring at B must be compressed against the 0.2-lb block so that when the block is released from B it slides along the smooth surface and reaches point A. Express your answer in inches to three significant figures. x = A vec Submit Request Answer Provide Feedback ? in. Next >Q2/scale the Rhombus defined by the points p1=( 3,1), p2=(5,3), p3=(3,5) & p43(1,3) by a scale factor of 1/2 keeping the first point in the same locationUnder some circumstances when two parallel springs, with constants k₁ and k2, support a single mass, the effective spring constant of the system is given by k = 4k1k₂/(k₁ + k₂). A mass weighing 20 pounds stretches one spring 4 inches and another spring 2 inches. The springs are attached to a common rigid support and then to a metal plate. As shown in the figure, the mass is attached to the center of the plate in the double-spring arrangement. k₂ II k = 20 lb Determine the effective spring constant of this system. lb/ft Find the equation of motion x(t) if the mass is initially released from the equilibrium position with a downward velocity of 6 ft/s. (Use g for the acceleration due to gravity.) 32 ft/s² x(t) = ft