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- Scenario: You have been tasked with building a URL file validator for a web crawler. A web crawler is an application that fetches a web page, extracts the URLs present in that page, and then recursively fetches new pages using the extracted URLs. The end goal of a web crawler is to collect text data, images, or other resources present in order to validate resource URLs or hyperlinks on a page. URL validators can be useful to validate if the extracted URL is a valid resource to fetch. In this scenario, you will build a URL validator that checks for supported protocols and file types.correct error // testing for uplaoding files WebElement upload=driver.findElement(By.id(“inputGroupFile02));upload.sendKeys("E:\\6th semester\\software testing");ONLY ReadInputFile.java file can be edited with New JAVA CODE ONLY new code can be added between 21 and 23 (as seen in image). cashew1.txt 47 cashew2.txt 21 cashew3.txt 25
- If wrong answer this time will downvote it Create a class with a static main that tests the ability to resolve and print a Path: • Create an instance of a FileSystem class. • Resolve an instance of a Path interface from a directory path and filename. • Print the constructed Path with System.out.println() method. 2. Create a class with a static main that tests the ability to resolve and print a Path: • Create an array of Path class. • Instantiate instances of Path with absolute and relative paths. • Print the constructed elements of the array of Path class with System.out.println() method. 3. Create a class to test serialisation class that implements serializable, it should implement the following: • A static void method that serialises an object. • A static void method that deserializes an object. • A static main method that tests the two by moving an object from one to the otherIn JAVA 1. Adapt the demo that creates 3 separate threads. 2. The difference will be that instead of printing, the threads will have to open a file and read from the file. Finally they will print the contents of the file. There will be three files. FileA.txt, FileB.txt, File100.txt. As you can imagine, file A will contain only a characters, file B will contain only b characters, File100 will contain the numbers 1 through 100. 3. Finally, you will have to implement the yield(), sleep(), OR join() methods somewhere in your program. You only need one implementation somewhere in your code.Write a Java GUI program using BufferedReader that asks the user to input the file to be opened. If said file exists, the program shows its first line text. It is given that you have myFile.txt in your working directory with the following text. Sample Output:
- The provided Linux runtime memory image shows the address space for a program named exam that is running in memory. If the exam program calls the printf function that is defined in the libc library, then what type of linking was performed? 00400000-004b6000 x-xp 00000000 00:75 163237418 006b6000-006bc000 rw-p 000b6000 00:75 163237418 806bc000-006bd000 rw-p 00000000 08:00 0 820bc800-828df000 rw-p 00000000 08:00 0 7ffc02014000-7ffc02035000 rw-p eeeeeeee 00:00 0 A. Static OB. None are correct OC. Global OD. Dynamic Reset Selection /mnt/learncli/workdir/exam /mnt/learncli/workdir/exam [heap] [stack]Create a program that extracts words from a website and inserts them into a text file. The program should prompt the user to insert a URL link, extract words from website, ask the user to name a new file name for extracted words and place them on the a txt file.Implement a simple version of the linux grep command in C++. grep - Looks through a file, line by line, trying to find a user-specified search term in the line. If a line has the word within it, the line is printed out, otherwise it is not. Use the system calls open(), getline(), close(). Requirements (examples run from. terminal) Your program grep is always passed a search term and zero or more files to grep through (thus, more than one is possible). It should go through each line and see if the search term is in it; if so, the line should be printed, and if not, the line should be skipped. [terminal]$ ./grep ! main.cpp main2.cppcout << "Hello, World!";cout << "Programming is great fun!"; The matching is case sensitive. Thus, if searching for world, lines with World will not match. Lines can be arbitrarily long (that is, you may see many many characters before you encounter a newline character, \n). grep should work as expected even with very long lines. For this,…
- Correct the code: 1. import java.io.File; // Import the File classimport java.io.IOException; // Import the IOException class to handle errorspublic class CreateFile {public static void main(String[] args) {try {File myObj = File("filename.txt");if (myObj.createNewFile() {System.out.println("File created: " + getName());} else {System.out.println("File already exists.");}} catch (IOException) {System.out.println("An error occurred.");}}}Output:File created: filename.txt 2. import java.io.File; // Import the File classimport java.io.FileNotFoundException; // Import this class to handle errorsimport java.util.Scanner; // Import the Scanner class to read text filespublic class ReadFile {public static void main(String[] args) {myObj = new File("filename.txt");Scanner myReader = Scanner(myObj);while (myReader.hasNextLine()) {String data =nextLine();System.out.println(data); 4}myReader.close();catch (e) {System.out.println("An error occurred.");e.printStackTrace();}}}Output:Files in…In ......... system libraries and program code combined by the loader into the binary program image.A. Dynamic Binding B. Dynamic linking C. Static linking D. All of the abovepublic static void doSomething(String str) { System.out.println(str); } public static void main(String[] args) { try { Scanner fileHandler = new Scanner(new File("file.txt")); while(fileHandler.hasNext()) { doSomething(fileHandler.nextLine()); } }catch(IOException io) { // what happens if the file is not there?? } } Contents of file.txt are: Hello CS 1 I hope you are enjoying, yourself!