Q1) If BX=1000, DS=0200, SS=0100, CS=0300 and AL=EDH, for the following instruction: MOV [BX] + 1234H, AL Find the physical address in the memory.
Q: (a) Set a base address for a generic PIO at 0x10008000 called pioBase. Assume this is just an 8-bit…
A: Change in memory location an interrupt is set to send signals, when we change in memory.
Q: 3. Translate following program into compiled MIPS code. Assume that g, c, i are in $s0, $s1, $s2…
A: Given: We have to translate the following program into Compiled MIPS code . Assume that g, c , i…
Q: if BX=1000, DS=0400, and AL=EDH, for the following instruction: MOV [BX] + 1234H, AL. the physical…
A: The answer will be:- 6234H
Q: JumpOffset X This instruction will jump to the address calculated by adding the given address, X, to…
A: The answer is
Q: e instruction, Add #45,R1 does Adds 45 to the value of Rl and stores it in R1 Adds the value of 45…
A: Add #45, R1 is instruction for addition.
Q: The physical address of the following memory location specified in the instruction MOV [BX-0200H],…
A: The physical address for the instruction MOV [BX + 0200H], AL is 61200H.
Q: Q1) If BX=1000, DS=0200, SS=0100, CS=0300 and AL=EDH, for the following instruction: MOV [BX] +…
A: Given Values are:- BX= 1000, DS= 0200, SS=0100, CS=0300, AL=EDH The instruction is MOV [BX]+1234H,…
Q: 2.12 Assume that registers $s0 and $s1 hold the values 0x80000000 and OXD0000000, respectively.
A:
Q: 7-lf we assume we place the following MIPS code starting at location 8000 in memory, what is the…
A: 1) SLT $t2 $zero $t0 Binary: 00000000000010000101000000101010 Hex: 0x0008502a 2) BNE $t2 $zero…
Q: Q2: Calculate the physical address for the following instruction (MOV DX, [SI]) knowing that the…
A:
Q: (B) - Identify the addressing mode for the following instructions then compute the physical address…
A: The physical address of any instruction can be calculated by the formula: PA =Segment reg…
Q: Assume the following contents of registers and quadwords in memory: Location Value %rax Ox8 %rbx Ox1…
A: leaq s,d Here, “s” denotes source, “d” denotes destination. This instruction loads the address of…
Q: Q3: The original contents of CX, AX, memory location Beta, and carry flag (CF) are FFE116, 11AB16,…
A: Answer: I have given answered in the handwritten format
Q: "uppose we have the instruction Load 500. Given that memory and register R1 contain the values…
A: Instruction Load is 500 So, Assuming R1 is implied in the indexed addressing mode. Immediate…
Q: 1) Write simple instructions (simple program) that will add two consecutive bytes of data storied…
A: Ans 1) CMP and SUB, both the instructions subtract one from the other. But the difference is, CMP…
Q: Assume the following values are stored at the indicated memory addresses and registers: Address…
A: Firstly movl moves a long (32-bits) from source to destination. Here we are given :
Q: Convert the following C code to MIPS assembly code. Assume the base address of array is stored in…
A: Find: Write MIPS assembly code for the given c code instruction. Answer: Please find the MIPS…
Q: 1. The hypothetical machine of Figure 3.4 also has two I/O instructions: In these cases, the 12-bit…
A:
Q: If JMP 90 instruction reside at memory location OFCDA then, the memory * location of the next…
A: Solution:-
Q: (i) Identify the addressing mode used in each instruction in the following code segment, and give…
A: The way of specifying data to be operated by an instruction is known as addressing modes. This…
Q: H.W. an instruction is stored al location 300 with its address field al location 301. The address…
A: Step 1 The answer is given in the below step
Q: Q:find the actual address for the ..il following instruction assume X=38 and R index=DDCE8 hex LOAD…
A: Given: X = 38 Ri = DCE8
Q: Q:find the actual address for the following instruction assume X= (27)hex and R index=DBC9 LOAD…
A: Question:
Q: 3. Using the given Instruction Table, write the instruction in hexadecimal number: Get the value…
A: Here we write the instruction and explain it and write it in hexadecimal number Answer a) we use the…
Q: 8086Microprocessor 1. Write a piece of code that exchanges a block of 236 bytes stored at locations…
A: Write 8085 code exchanges a block of bytes to another block Algorithm: Take a count equal to 256…
Q: b. i. Using a detailed state diagram, explain how the instruction cycle can be expanded including…
A: Given data: An instruction is stored at memory address 100. Assume that the address field of…
Q: 22. Suppose that DS = 0200H, BX = 0300H, and DI = accessed by each of the following instructions,…
A: The Answer is
Q: Endianness Assume that a snippet of memory is shown below (in hex), starting with the byte at…
A: Dear Student, In big-endian machine the data is stored in the same order ie the byte which is first…
Q: Write simple instructions (simple program) that will add two consecutive bytes of data storied with…
A: In a direct addressing mode, the data to be worked upon is in a memory location and as an operand,…
Q: Q:find the actual address for the following instruction assume X=38 and Rindex=DCE8 LOAD X(Ri), A…
A: Given, R index = DCE8 Value of X = 38 The above value is the offset value which is an integer value…
Q: Q:find the actual address for the following instruction assume X=38 and R index=DCE8 hex LOAD X(Ri),…
A: Solution:-
Q: An instruction at address 021 in the basic computer has I = 0, an operation code of the AND…
A: According to the information given:- We have to follow the instruction to determine over the…
Q: (B)- Identify the addressing mode for the following instructions then compute the physical address…
A: 1)LDS [FFH],SI Register indirect addressing mode. In this addressing mode, The address field of…
Q: Microprocessor Hw Q1 Execute the following code and show the contents of the registers: LDI R16,$03…
A: A CPU or processor register is one of a small set of data holding places that are part of the…
Q: 80/20 rule states that 80% of the instruction ios executed and 20% of the instruction is generated…
A: This rule is discovered by Wilfredo pareto and it is also called as pareto principle. it is a very…
Q: Question 4 Endianness Assume that a snippet of memory is shown below (in hex), starting with the…
A: 4. Given, Address starts with 0x10. Data is : | 77 | AB | 69 | CA | 0D | F0 | 12 | BE | The system…
Q: Q:find the actual address for the following instruction assume X=A6 and PC=8B79, LOAD X(PC), D…
A: Given: X = A6 PC = 8B79 LOAD X(PC), D Find the actual address.
Q: a=0.0; i=10; while (i>0) { i=i-1; a=a*B[i]; } where a is a single-precision floating-point number…
A: sub.s $f0, $f0, $f0 #single precision floating point for subtraction operations addi…
Q: 8 Find the physical address of the memory locations referred in the following instructions if…
A: 8086, via its 20 bit address bus, can address 220 = 1,048,576 or 1 MB of different memory locations.…
Q: After the instruction Idr ro, [r1] is executed, what is the content of ro? A. The 8-bit value…
A: content of r0 after the instruction executed
Q: For the MIPS assembly instructions below, what is the corresponding C statement? Assume that the…
A: The MIPS assembly line: This MIPS processor's machine code is simply known as MIPS assembly code.…
Q: Write at most two instructions to move ONLY the fourth byte value in the register ($s1) into the…
A: This is how you can do this easily. Note: We are given the data in bytes so de defined the variable…
Q: 1- The instruction : MOV [Dx+SI], Ax is allowed T 2- The instruction : MOV ES:[SI], Ax is not…
A: 1. True The instruction is valid 2. False The instruction is invalid, since in based index…
Q: iv) Using the following instruction format, a total of registers can be addressed 8 7 10 OP code…
A: 4) 4.10
Q: Consider the following code sequence, (i) MOV. B, R0 ADD C, R0 MOV R0, A Calculate the…
A: The Answer is
Q: Q:find the actual address for the following instruction assume X=38 and ?=R index=DCE8 LOAD X(Ri), A…
A: Given data: R index = DCE8 X = 38 Now find the actual address. The instruction is: LOAD X(Ri), A
Q: If BX=1000, DS=0200, SS=0100, CS=0300 and AL=EDH, for the following instruction: MOV [BX] + 1234H,…
A: Answer: It is a base addressing mode. Effective address of the operand obtained by adding direct or…
Q: Assume that two numbers: dividend and divisor are saved in memory address M1 and M2 respectively.…
A:
Q: 1.An address field in an instruction contains decimal value 24. Where is the corresponding operand…
A: 1.An address field in an instruction contains decimal value 24. Where is the corresponding operand…
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- please give implementation of unsigned int getL1SetID(u_int32_t address){///// IMPLEMENT THIS /////return 0;}unsigned int getL2SetID(u_int32_t address){///// IMPLEMENT THIS /////return 0;}unsigned int getL1Tag(u_int32_t address){///// IMPLEMENT THIS /////return 0;}unsigned int getL2Tag(u_int32_t address){///// IMPLEMENT THIS /////return 0;}The memory location at address of 0X003FB01 contains 1-byte memory variable J (0010_0001), and the memory location at the address of 0X003FB02 contains 1-byte memory variable K (0001 0010), see figure below. There is a 2-byte variable M which hold binary information M (1110 0101 0000 1i11). What is the address in hexadecimal format for 2-byte memory variable M, following little Endian computer? 7 Address in Data in Hex. Format Hex. Format 0X003FBF04 1110 0101 M OX003FBF03 0000 1111 0X003FBF02 0001 0010 0X003FBF01 0010 0001 J Its address in hexadecimal is 0X003FBF02. а. Its address in hexadecimal is 0×003FBF03. O b. Its address in hexadecimal is 0X003FBF04. Its address in hexadecimal is 0×003FBF01. d.Student information is being held in a data area, where each student record has the following format: The first nine bytes are the student number, held in ASCII The next byte is the course mark The next word is the section identifierThere are well over three hundred such student records that have been loaded sequentially into memory starting at address $10000. The last record loaded is a dummy record with a section identifier of $FFFF, to show the end of the records.Write an assembler subroutine GetMax that will scan the entire list and find the highest mark. If there is a tie, the first student in the list with the highest mark should be found. The subroutine should return the starting address of this record in address register a3.
- You're not sure what the data represents, but you've been told it uses a dual layer obfuscation as follows: Hex with "\x" delimiter Base64 with standard alphabet After you de-obfuscate the given Hex dats, what information do you find? Do some research. What have you found? NOTE: DO NOT BROWSE THESE! Hint: focus on the strings following "/". Essentially, this practical has two stages: 1. De-obfuscate the Hex and give the output. 2. Research the nature of what you found and identify it.Suppose that you have a UNIX file system where the disk block size is 4096 bytes. Disk addresses and file block pointers take 32 bits (4 bytes), and the i-node contains 12 direct pointers, one single-indirect pointer and one double-indirect pointer. Assume an index block is the same size as a data block (both 4096 Bytes). If there is a file having 50,000 bytes of data and it is never been accessed, we only assume the file's i-node is in memory, but none of the rest of the file. If the user process wants to access to read the entire file into the memory, how many I/O operations would be needed? O a. 15 O b. 12 O c. 14 O d. 13A ring buffer, often known as a circular queue, is a fixed-size N FIFO data structure. It can be used to transport data between asynchronous processes or to store log files. When the buffer is empty, the consumer must wait for data to be deposited; when the buffer is full, the producer must wait for data to be deposited. Create a RingBuffer API as well as an implementation that uses an array representation (with circular wrap-around).
- Let's say p contains a memory address and the 8 bytes in memory beginning at that address are (in hex): 01 12 23 34 45 56 67 78. If p's type is "uint32_t *", what is the value of x on a little-endian computer after executing: uint32_t x = p[0]; Ox01122334 Ox0112233445566778 Ox34231201 Ox7867564534231201 O O O OLet's say p contains a memory address and the 8 bytes in memory beginning at that address are (in hex): 01 12 23 34 45 56 67 78. If p's type is "uint32_t *", what is the value of x on a big-endian computer after executing: uint32_tx = p[0]; Ox01122334 Ox0112233445566778 Ox34231201 Ox7867564534231201 O 0 0 OLet's say that p is a pointer to memory and the next six bytes in memory (in hex) beginning at p's address are: aa bb cc dd ee ff. What value would be in x if the following code is run on a little- endian computer? uint16_t *q uint16_t x = (uint16_t *)p; q[0]; aa aabb bbaa aabbccdd ddccbbaa
- A ring buffer, or circular queue, is a FIFO data structure of a fixed size N. It is useful for transferring data between asynchronous processes or for storing log files. When the buffer is empty, the consumer waits until data is deposited; when the buffer is full, the producer waits to deposit data. Develop an API for a RingBuffer and an implementation that uses an array representation (with circular wrap-around)Suppose that DS=1000H, SS= 2000H, CS=3000H, ES=4000H, BP=FFH, BX=FFFFH and DI=5H.i. Which memory locations are addressed by: MOV DL, [BP]?ii. Which memory locations are addressed by: MOV EAX, [BX+DI]?Write a device driver for a character device which implements a simple way of message passing. The kernel maintains a list of messages. To limit memory usage, we impose a limit of 4KB = 4*1024 bytes for each message and also impose a limit of the total number of messages stored in the kernel, which is 1000. Your device driver should perform the following operations: * When the module is loaded, the device is created. An empty list of messages is created as well. * Removing the module deallocates all messages, removes the list of messages and removes the device. * Reading from the device returns one message, and removes this message from the kernel list. If the list of messages is empty, the reader returns -EAGAIN. * Writing to the device stores the message in kernel space and adds it to the list if the message is below the maximum size, and the limit of the number of all messages stored in the kernel wouldn't be surpassed with this message. If the message is too big, -EINVAL is…