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- Q1: Draw just the Free Body Diagram of the following figures. D Figure (1) Figure (2) Figure (3) T 30° 45° 60° - Figure (4) Figure (5) 26 kN 250 N 30 13 12 30 0.15 m 0.4 m B. 0 m 2 m 4 mH.W no. 2 Q1) 28 N.m torque is needed to turn the bolt around its axis as shown in the Figure (1) below. Find the force F and the forces between the wrench's smooth face jaws and the hexagonal bolt head's corners A and B. Suppose the wrench fits on the bolt simply such that connection is only formed at corners A and B. 150 mm 14 mmH.W no. 2 Q1) 28 N.m torque is needed to turn the bolt around its axis as shown in the Figure (1) below. Find the force F and the forces between the wrench's smooth face jaws and the hexagonal bolt head's corners A and B. Suppose the wrench fits on the bolt simply such that connection is only formed at corners A and B. 150 mm 14 mm Figure (1) Q2) Three cables are joined at the junction ring C. Determine the tension in cables AC and BC caused by the weight of the 30-kg cylinder. 45 15 30 30 kg B Figure (2) Q3) A beam is loaded and supported as shown in Figure (3). The beam has a uniform cross section and a mass of 20 kg. Determine the reaction at support A and the tension T in the cable.
- H.W no. 2 Q1) 28 N.m torque is needed to turn the bolt around its axis as shown in the Figure (1) below. Find the force F and the forces between the wrench's smooth face jaws and the hexagonal bolt head's corners A and B. Suppose the wrench fits on the bolt simply such that connection is only formed at corners A and B. 150 mm 不 14 mm Figure (1) Q2) Three cables are joined at the junction ring C. Determine the tension in cables AC and BC caused by the weight of the 30-kg cylinder. A 45 15° 30 kg 30 B Figure (2) Q3) A beam is loaded and supported as shown in Figure (3). The beam has a uniform cross section and a mass of 20 kg. Determine the reaction at support A and the tension T in the cable.Q1: In the below drawings, three unbalanced masses and related details are provided. Please answer the following questions. a) a balancing mass is to be located at rp = 50 mm, then what would be the balancing m1 m1 650 mm 200 mm m2 mass (m,) and its angular position (Op) (Please use the r2 m2 A graphical method) r3 m3 15 m3 b) If the system is not balanced what would be the reaction forces at A and B. (FA, FB=?) n = 150 rpm r; = 30 mm m, = 1 kg r2 = 20 mm 40 тm 13= m, =3 kg m; = 2 kg k = please choose an appropriate scaling factor yourself SHOT ON MI 6 MI DUAL CAMERAGIVEN: W= 595 N GIVEN: ANGLE A= 44 DEGREE GIVEN: ANGLE B= 14 DEGREE ANSWER: SOLVE (A) IN UNIT CM SOLVE (B) IN UNIT N-CM SOLVE (C) IN N-CM PLS SHOW COMPLETE SOLUTION AND WRITE LEGIBLY AND SHOW THE FREE BODY THE DIAGRAM
- Set P₁= 2 kN and P₂ = 1.5 kN. (Figure 1) Figure 30° -3m D 30° 3m 1 of 1 Copyright @ 3032 D.Cables of negligible weight support the loading shown. (Figure 1) If W1 = 5.00 lb , W2 = 71.0 lb , yB = 4.50 ft , yc = 7.50 ft , yp = 2.50 ft , and æc = 2.00 ft , find æB- Express your answer numerically to three significant figures in feet. • View Available Hint(s) It vec TB = ft Figure < 1 of 1 W2In the graph the force versus displacement of a spring is given (the spring is shown in a separate figure--see below). The x-axis range is ±2 cm. The y-axis range is tFs, where Fs = 220 N. How much work does the spring do on the block (the mass "m") when the block moves from x₁ = 7.6 cm to 4.3 cm? W J y F. X -1.5 -0.5 0 10.5 1 1.5 -F How much work does the spring do on the block (the mass "m") when the block moves from x; = 7.6 cm to -7.6 cm? W = Question Help: Read Submit Question m
- 5 - note: ignore weight of the bar.A) ( - 6/7)T(CB) + A(y)=0 (A=reaction force at A, A(x), A(y), A(z) are components of force A)B) (2/7)T(CB)+A(x)=392 (A=reaction force at A, A(x), A(y), A(z) are components of force A)C) A(x)=2A(y) (A=reaction force at A, A(x), A(y), A(z) are components of force A)D) A(x)=5A(z) (A=reaction force at A,A(x), A(y), A(z) are components of force A)A load weighing P kN as with AB, AC and AD cables such as are carried. Points A and B are x-axis, C and D points are on the y-z plane. Specific to your name in the data table AB, AC and AD cable using ratings Calculate the forces. P (kn) = 440 L1 (m) = 11 L2 (m) = 10 L3 (m) = 16 %3D %3D %3D L4 (m) = 18 L5 (m) = 16 L6 (m) = 5 %3D %3D %3DThe figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the bronze rod caused by the 42563-Nload, using the following data: length of steel = 1.56 m, length of bronze = 2.18 m Area of steel = 563 mm, Area of bronze = 233 mm Modulus of elasticity of steel = 193 Gpa, Modulus of elasticity of bronze = 82 Gpa x = 0.69 m, y = 1.03 m, and z = 0.79 m.