Problem 9.82Figure50:1JINI.IdealZbe1:20IdealZL1 of 1Part AFind the impedance Zab in the circuit in (Figure 1) if Z=200/- 55° 2.Enter your answer using polar notation. Express argument in degrees.Zab=VAΣ vecSubmitxaxbb√x √√x 1x1 T20 (X)*< Return to AssignmentYou have already submitted this answer. Enter a new answer.No credit lost. Try again.Previous Answers Request AnswerProvide FeedbackX.10nX?Ω

Problem 9.82 Figure a● Zab be 50:1 Ideal 1:20 || Ideal ZL < 1 of 1 > Part A Find the impedance Zab in the circuit in (Figure 1) if ZL=200Z - 55° N. Enter your answer using polar notation. Express argument in degrees. Zab = | ΑΣΦmit | vec| Submit xa Xb a You have already submitted this answer. Enter a new answer. No credit lost. Try again. < Return to Assignment √x √√x 1x1 T20 (X)* X.10n Previous Answers Request Answer ? Provide Feedback X wwwww S2

Problem 9.82 Figure a● Zab be 50:1 Ideal 1:20 || Ideal ZL < 1 of 1 > Part A Find the impedance Zab in the circuit in (Figure 1) if ZL=200Z - 55° N. Enter your answer using polar notation. Express argument in degrees. Zab = | ΑΣΦmit | vec| Submit xa Xb a You have already submitted this answer. Enter a new answer. No credit lost. Try again. < Return to Assignment √x √√x 1x1 T20 (X)* X.10n Previous Answers Request Answer ? Provide Feedback X wwwww S2

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.61P

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google.com/forms/d/e/1FAlpQLScF2Wzu92iVI-tEM2nxdhqXrGdR460G4QCTxaUZZeC678PqTg/formResponse مطلوب /06 *:The potential at point P due to Q1 and Q2 is Q, = 1x10-12C 0.5 m 0.5 m Qz = 1x10-12C %3D 50 cm 0.01797 V Ov O -0.01271 V O 0.01271 V O Insert PIC F10 F11 F12 F6 F7 FB Backspace 9 € P Enter H
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