Preliminary analyses indicate that you can consider the assumptions for using nonpooled t-procedures satisfied. Researchers obtained the following data on the number of acute postoperative days in the hospital using the dynamic and static systems. Obtain a 90% confidence interval for the difference, ₁-₂, between the mean numbers of acute postoperative days in the hospital with the dynamic and static systems. (Note: x₁ = 6.50, s₁ = 1.51, x₂ = 11.33, and $₂ = 3.39) The 90% confidence interval is from to (Round to three decimal places as needed.) 7 7 10 6 8 10 Dynamic 5 8 Static 11 7 4 7 6 8 13 4 8 17
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- Avalanches can be a real problem for travelers in the western United States and Canada. Slab avalanches studied in Canada had an average thickness of u = 67 cm. A sample of 31 avalanches in the U.S. gave a sample mean of = 63.0 cm. It is known that o = 10.3 cm for this type of data. Use a 0.03 level of significance to test the claim that the mean slab thickness of avalanches in the United States is different from that in Canada. Use the P-Value Approach. What are the hypotheses for this problem? А: Но и 3D 63.0 ст us На и + 63.0 ст B: Но и 63.0 ст С: Но и %3D 67 ст us HA и < 67 ст D: Ho u = 67 cm vs HA H# 67 cm B O AAvalanches can be a real problem for travelers in the western United States and Canada. Slab avalanches studied in Canada had an average thickness of µ = 67 cm. A sample of 31 avalanches in the U.S. gave a sample mean of = 63.0 cm. It is known that o = 10.3 cm for this type of data. Use a 0.03 level of significance to test the claim that the mean slab thickness of avalanches in the United States is different from that in Canada. Use the P-Value Approach. What is the Decision for this problem? O There is not sufficient evidence at the 0.03 level of significance to show that the mean slab thickness of avalanches in the United States is different from that in Canada. There is sufficient evidence at the 0.03 level of significance to show that the mean slab thickness of avalanches in the United States is less than that in Canada. There is sufficient evidence at the 0.03 level of significance to show that the mean slab thickness of avalanches in the United States is different from that in…Arsenic is a compound that occurs naturally in very low concentrations. Arsenic blood concentrations in healthy individuals are Normally distributed with a mean of 3.2 mg/dl. Some areas of the United States have naturally elevated arsenic levels in the ground and water supplies. Researchers took a sample 20 water samples from a particular area and measured the arsenic levels in each of the 20 water samples. They want to determine if there is sufficient evidence to conclude that the arsenic level in that area is higher than 3.2 mg/dl. hypothesis test for one population mean (unknown population standard deviation) confidence interval estimate for one population mean (unknown population standard deviation) hypothesis test for population mean from paired differences confidence interval estimate for population mean from paired differences hypothesis test for difference in population means from two independent samples confidence interval estimate for difference in population means from two…
- A simple linear regression model was created based on 25 samples. The 95% confidence interval for the estimate of B, is (1.5, 4.8). What is thet-statistic for B1? Report your answer in 3 decimal places.For each scenario, indicate whether the parameter of interest is one proportion , a difference in two proportions , one mean (μ), a difference in means from separate samples , or the mean difference from matched pairs data, . Each answer can be selected once, more than once, or not at all. A tire manufacturer tested the braking performance of one of its tire models on a test track, interested in how tires perform under both wet and dry pavement conditions. The company tried the tires on 18 different car models, recording the stopping distance for half of them on wet pavement and the other half of dry pavement. Student Computing Services surveys a random sample of students to compare the percent of students that have PCs to the percent of students that have Macs. Married couples are asked about the number of hours of sleep they get each night. We want to see if husbands get more sleep than their wives. 36 of 75 patients receiving a treatment experienced pain relief, while only…Research indicates that there may be a relationship between caffeinated coffee consumption and risk of depression in women. Provided is data on the amount of caffeinated coffee consumed and whether the woman was diagnosed with clinical depression. Of interest is to see if there is evidence of an association between caffeinated coffee intake and clinical depression in women. Using the provided output, what is the pvalue and what are the results of the test? Caffeinated coffee Depression <1 cup/wk >=1 cup/day 2-3 cups/day 4+ cups/day Total Yes 670 1278 564 95 2607 No 11545 22573 11726 2288 48132 Total 12215 23851 12290 2383 50739 Pearson's Chi-squared testdata: coffeeX-squared = 19.472, df = 3, p-value = 0.0002184 A. pvalue=3 <= alpha(0.05), H0 is rejected. There is an association between depression and caffeine intake in women B. pvalue=19.472 <= alpha(0.05), H0 is rejected. There is an association between depression and caffeine intake in…
- The price paid for a new phone of a particular model follows a Normal distribution with mean μ=750 and standard deviation σ= 42. What proportion of these phones are purchased for more than 821 dollars? Give your answer to four decimal places. A study of 25 online jewelry retailers was done to find the statistical relationship between the price yyin dollars of a diamond ring and the weight xxin carats of the diamond. Based on this data the following least-squares regression line was found: y^=−6047.75+11975.14x What is the predicted price of diamond ring a 2.2 carat diamond using this regression line. Round your answer to two decimal places. A study of 25 online jewelry retailers was done to find the statistical relationship between the price yy in dollars of a diamond ring and the weight xx in carats of the diamond. Based on this data the following least-squares regression line was found: y^=−6047.75+11975.14x One online retailer sells a 3.00 carat diamond ring for 28,999…Sulfur dioxide (SO2) pollution is a known cause for corrosion of exposed steel. To document this effect in actual conditions, steel weight loss (gm/m3/yr) was measured at 36 locations in a large city, along with the rate at which SO2 was deposited (mg/m2/day). Obtain an estimate of the correlation between steel loss and sulfur dioxide deposition rate and interpret it. Give a 95% confidence interval for its value. SO2 Loss 22.6 580 26.1 563 19.1 339 17.2 346 25 623 16.8 420 42.7 951 30.4 794 17.9 461 30.4 757 27.8 573 27.8 656 33 990 14.2 551 37.4 856 16.2 443 27.7 802 22.7 657 21 495 15.8 496 13.7 353 24.7 724 23.7 602 30.7 639 33.5 813 30.2 770 20.1 556 22.8 557 39.9 1001 15.5 432 40.4 940 27.9 687 39.4 919 25.1 590 28.6 640 29.7 702A new cream that advertises that it can reduce wrinkles and improve skin was subject to a recent study. A sample of 68 women over the age of 50 used the new cream for 6 months. Of those 68 women, 39 of them reported skin improvement(as judged by a dermatologist). Is this evidence that the cream will improve the skin of more than 40% of women over the age of 50? Test using a= 0.05 (a) Test statistic: z= (b) The final conclusion is...A. There is not sufficient evidence to reject the null hypothesis that p=0.4 . That is, there is not sufficient evidence to reject that the cream can improve the skin of more than 40% of women over 50.B. We can reject the null hypothesis that p=0.4 and accept that p>0.4. That is, the cream can improve the skin of more than 40% of women over 50.
- Peak expiratory flow (PEF) is a measure of a patient’s ability to expel air from the lungs. Patients with asthma or other respiratory conditions often have restricted PEF. The mean PEF for children free of asthma is 306. An investigator conducts a study to investigate whether there is a difference in mean PEF in children with chronic bronchitis as compared to those without asthma or other respiratory conditions often have restricted PEF. Data on PEF are collected and summarized below. Based on the data, is there statistical evidence of a lower mean PEF in children with chronic bronchitis as compared to those without? Run the appropriate test at = 0.05. Group Number of Children Mean PEF Std PEF Chronic Bronchitis 25 281 68 No Bronchitis 25 319 74Peak expiratory flow (PEF) is a measure of a patient’s ability to expel air from the lungs. Patients with asthma or other respiratory conditions often have restricted PEF. The mean PEF for children free of asthma is 306. An investigator conducts a study to investigate whether there is a difference in mean PEF in children with chronic bronchitis as compared to those without asthma or other respiratory conditions often have restricted PEF. Data on PEF are collected and summarized below. Based on the data, is there statistical evidence of a lower mean PEF in children with chronic bronchitis as compared to those without? Run the appropriate test at alpha = 0.05. Group Number of Children Mean PEF Std Dev PEF Chronic Bronchitis 25 281 68 No Chronic Bronchitis 25 319 74