Provide correct solution PIV (PRV)• It is the voltage rating that must not be exceeded in the reverse-bias region, orthe diode will enter the Zener avalanche region.●Applying Kirchhoff's voltage law, it is fairly obvious that the PIV rating ofthe diode must equal or exceed the peak value of the applied voltage.Prove that PIV (Use KVL)VmPIV rating VmV (PIV)1=0JRhalf-wave rectifierProve, PIV>=V(m)V=IR=(0)ROVFIG. 2.52Determining the required PIV rating for thehalf-wave rectifier.11:02 PM21

Peak inverse voltage is the maximum reverse bias voltage that can be applied to the circuit. The…

PIV (PRV) • It is the voltage rating that must not be exceeded in the reverse-bias region, the diode will enter the Zener avalanche region. Applying Kirchhoff's voltage law, it is fairly obvious that the PIV rating the diode must equal or exceed the peak value of the applied voltage. • Prove that PIV (Use KVL) . Vm PIV rating Vm V (PIV) 5 1=0 half-wave rectifier V₁=IR=(0)R=0 V FIG. 2.52 Determining the required PIV rating for the half-wave rectifier.

PIV (PRV) • It is the voltage rating that must not be exceeded in the reverse-bias region, the diode will enter the Zener avalanche region. Applying Kirchhoff's voltage law, it is fairly obvious that the PIV rating the diode must equal or exceed the peak value of the applied voltage. • Prove that PIV (Use KVL) . Vm PIV rating Vm V (PIV) 5 1=0 half-wave rectifier V₁=IR=(0)R=0 V FIG. 2.52 Determining the required PIV rating for the half-wave rectifier.

Electric Motor Control

10th Edition

ISBN:9781133702818

Author:Herman

Publisher:Herman

Chapter59: Motor Startup And Troubleshooting Basics

Section: Chapter Questions

Problem 12SQ: How is a solid-state diode tested? Explain.

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