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Pentane (C5H12) is a liquid with density of 0.929 g/mL at 25 °C. Find the true mass of pentane when the mass in air is 14.82 g. Assume air density is 0.0012 g/mL.

Pentane (C5H12) is a liquid with density of 0.929 g/mL at 25 °C. Find the true mass of pentane when the mass in air is 14.82 g. Assume air density is 0.0012 g/mL.

Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter17: Electrochemistry
Section: Chapter Questions
Problem 147CP: The measurement of pH using a glass electrode obeys the Nernst equation. The typical response of a...
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Táke off any gridlines and add a title and axes labels. Add the trendline and the relevant equation. b) If a sample was analyzed and the current was measured to be 5.18 mA, what is the concentration of analyte in the sample? 5.18= 3.403x + 1.9232 3.2368=3.4403 x 0.947: x Pentane (C5H12) is a liquid with density of 0.929 g/mL at 25 °C. Find the true mass of pentane when the mass in air is 14.82 g. Assume air density is 0.0012 g/mL.
Transcribed Image Text:Táke off any gridlines and add a title and axes labels. Add the trendline and the relevant equation. b) If a sample was analyzed and the current was measured to be 5.18 mA, what is the concentration of analyte in the sample? 5.18= 3.403x + 1.9232 3.2368=3.4403 x 0.947: x Pentane (C5H12) is a liquid with density of 0.929 g/mL at 25 °C. Find the true mass of pentane when the mass in air is 14.82 g. Assume air density is 0.0012 g/mL.
Expert Solution
Step 1

The true mass of pentane is calculated by using formula - 

m = m' 1-dadw1-dad

where 

  • m = true mass 
  • m' = mass of pentane 
  • da = density of air 
  • dw = density of balance weight
  • d = density of pentane 
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