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Part 4 of 4 Remembering that sin² -112 2√27 t = cos 2t, we conclude that 2 sin2 t dt = -112- ΤΟ 2元

Part 4 of 4 Remembering that sin² -112 2√27 t = cos 2t, we conclude that 2 sin2 t dt = -112- ΤΟ 2元

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.4: Multiple-angle Formulas
Problem 41E
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Part 4 of 4 Remembering that sin² -112 2√27 t = cos 2t, we conclude that 2 sin2 t dt = -112- ΤΟ 2元
Transcribed Image Text:Part 4 of 4 Remembering that sin² -112 2√27 t = cos 2t, we conclude that 2 sin2 t dt = -112- ΤΟ 2元
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