My original question has already been answered, however, in Step 2 of the Expert Answer I would like clarification on how to compute the critical values manually - without the use of EXCEL, as mentioned in the respnse, so I need to know what formula do I use? Question: Prior to assessment of the outcome, the researchers did a manipulation check. Members of Groups 1 and 2 rated the attractiveness (on a 1 to 9 scale, with 9 being the most attractive) of the person in the photo. They reported that for the attractive photo, M = 7.53; for the unattractive photo, M = 3.20, F(1, 108) = 184.29. Was this difference statistically significant (using a = .05)? Expert Answer Step 1 It is given that the F-test statistic is 184.29, the degrees of freedom for first and second groups are 1 and 108, and the level of significance is 0.05. State the appropriate hypothesis: Null hypothesis: H0 : There is no difference between two groups. Alternative hypothesis: Ha : There is a difference between two groups. Step 2 Critical value: The critical value for 1 and 108 degrees of freedom with level of significance 0.05 is 3.93 using EXCEL formula F.INV.RT(0.05,1,108). Rejection rule: If test statistic greater than the critical value then reject the null hypothesis.
My original question has already been answered, however, in Step 2 of the Expert Answer I would like clarification on how to compute the critical values manually - without the use of EXCEL, as mentioned in the respnse, so I need to know what formula do I use?
Question:
Prior to assessment of the outcome, the researchers did a manipulation check. Members of Groups 1 and 2 rated the attractiveness (on a 1 to 9 scale, with 9 being the most attractive) of the person in the photo. They reported that for the attractive photo, M = 7.53; for the unattractive photo, M = 3.20, F(1, 108) = 184.29. Was this difference statistically significant (using a = .05)?
Expert Answer
It is given that the F-test statistic is 184.29, the degrees of freedom for first and second groups are 1 and 108, and the level of significance is 0.05.
State the appropriate hypothesis:
Null hypothesis:
H0 : There is no difference between two groups.
Alternative hypothesis:
Ha : There is a difference between two groups.
Critical value:
The critical value for 1 and 108 degrees of freedom with level of significance 0.05 is 3.93 using EXCEL formula F.INV.RT(0.05,1,108).
Rejection rule:
If test statistic greater than the critical value then reject the null hypothesis.
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