Mr. A is going to a hill station withhis family by driving a car. When thecar approaches the hill, he shiftsfrom high gear to low gear. He doesthis becauseNeither (A) nor (B) is correct.to increase the power outputfrom the tires.to increase the force pushingthe car forward.Both (A) and (B) are correct.

Gear ratio is inversely proportional to torque,power and speed Power = torque * angular speed High…

Mr. A is going to a hill station with his family by driving a car. When the car approaches the hill, he shifts from high gear to low gear. He does this because O Neither (A) nor (B) is correct. O to increase the power output from the tires. O to increase the force pushing the car forward. O Both (A) and (B) are correct.

Mr. A is going to a hill station with his family by driving a car. When the car approaches the hill, he shifts from high gear to low gear. He does this because O Neither (A) nor (B) is correct. O to increase the power output from the tires. O to increase the force pushing the car forward. O Both (A) and (B) are correct.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

Q2] Fill in the blank (9 Marks) 1- The critical resistance of the D.C. generator is the resistance of 2- A shunt generator running at 1000 r.p.m. has generated e.m.f. as 200V. If the speed increases to 1200 r.p.m., the generated e.m.f. will be nearly volt. 3- The current drawn by a 120 V D.C. motor of armature resistance 0.5 2 and back e.m.f. 110 V is ampere. 4- The direction of rotation of a D.C. motor can be reversed by V2 VI 5- A 440V/110Vtransformer has 1000 turns on the primary winding. The number of turns on the secondary is 6- The main purpose of performing open circuit test on a transformer is to measure its 7-A 3-phase, 4-pole, 50 Hz induction motor runs at a speed of 1440 r.p.m. The rotating field produced by the rotor rotates at a speed of respect to the rotor. r.p.m. with 8- The advantages of skewing in induction motor are and
15 Which of the following statements IS NOT CORRECT ? * the starting current of the induction motor is less than the rated current O the bigger is starting torque, the easier is starting of the induction motor O the slip of the induction motor increases with the increase of load O the starting torque of the motor is the torque at slip s=1
Q31. A d.c. shunt motor runs at 500 r.p.m. at 220 V. A resistance of 4.5 Q is added in series with the armature for speed control. The armature resistance is 0.5 Q. The current to stall the motor is 44 A 50 A 40 A 30 A 26 DC Motor Q&A Part 1 Tikrit University Dr Thamir Hassan Atyia
D1- Which DC motor's magnetic field gets stronger with an increase in mechanical load? a) series b) shunt c) compound d) "a" and "c", not "b" D2- The greater the mechanical load on a DC motor the faster it will turn. a) true b) false D3- Which of the following causes a DC shunt motor to automatically adjusts its input to take care of changes in mechanical load. a) the speed decreases with increases in load b) the cemf decreases with increases in load c) the supply current increases due to the decrease in cemf d) all of the above
A 14 kW, 160 V DC series motor is being supplied by a feeder with total resistance of 0.02 ohms and has an armature and field resistance of 0.02 ohms and 0.04 ohms respectively. Find the armature voltage. • 2 decimal places • No need unit Round your answer to 2 decimal places.
speed as a generator to the speed as a motor. The line current in each case being 80A 4- A 100kW, belt driven shunt generator running at 300rpm on 220V bus bars continue to run as a motor when the belt breaks, then taking 10kW. What will be its speed? Armature resistance is 0.0250; field resistance is 600; contact drop under each brush is 1V. Coloulot tonge vel
SHOW YOUR COMPLETE SOLUTION, ANSWER MUST BE IN 2 DECIMAL PLACES. SHOW WHAT IS GIVEN AND WHAT IS THE UNKNOWN. A 20KW short shunt generator with a terminal voltage of 250V has armature, series and shunt field winding have resistances of 0.05 ohms, 0.03 ohms and 100 ohms respectively. Calculate the total voltage generated in the armature when the brush drop is 1 V per brush and the feeder resistance is 0.5 ohm.
Select one: a. Range of speed between 1041 RPM and 2727 RPM b. Range of speed between 1222 RPM and 2360 RPM c. None d. Range of speed between 1818 RPM and 2220 RPM
Choose the correct answer/s. a) Which of the given losses is directly proportional to the square of speed? 1. Windage Loss, 2. Eddy's current Loss, 3. Both Windage and eddy's current loss, 4. Hysteresis loss and brush loss ..... b) Maximum power will be developed when back emf is 1. Equals to supply voltage, 2. Half to supply voltage, 3. Doubles to supply voltage, 4. All options are correct c) No-load saturation characteristics are plotted between 1. No-load voltage and field current, 2. No-load voltage and armature current, 3. Short circuit current and field current, 4. Short circuit current and armature current d) The current flowing in the conductors of a DC motor is ..... 1. D.C, 2. A.C, 3. D.C as well as A.C, 4. Transients e) The speed of a DC shunt motor is required to be more than Full Load speed. This is possible by 1. Increasing the armature current, 2. Decreasing the armature current, 3. Increasing the excitation current, 4. Reducing the field's current f) A simple method of…
Q2- Indicate whether the following statements are true or false and correct the false statements 1- are placed at the magneti tral axis erator is not red by 10au o generator ffected by load current 4- A lap winding is most suitable for higher voltage rating machines 5- In dc generator, the critical resistance can be increased by increasing its speed 6-In LAP winding the front pitch equal to (yr ye- yb). 7- The speed of d.c series motor is decreased if the armature current is decreased 8- The compensating winding carrying the field current 9- By tapping field method, the speed of d.c series motor can be controlled below rated value 10- To solve the Commutation Problem in small machines, this can be achieved by increasing the brush width
A- A d.c. series motor draws 22 A from a 240 V line while running at 840 rpm. It has an armature resistance of 0.6 2 and a series field resistance of 0.5 N. A diverter is to be added to the circuit so that the speed increases to1200 rpm while the line current increases to 28 A. Find the value of the diverter resistance Rd. B- 230v series motor is taking 50A .Resistance of armucture and series field winding is 0.22 and 0.12 respectively calculate: C- 1-power was tend in armature (500 kw D- 2-back e.m.f (205 v) E- 3-brush voltage (215) F- 4-mechincal power ( 10.25) kw
(U.E.I., 0.2) 9. A shunt generator on test is separately excited and driven at 1000 rev/min. The open-circuit test figures are as follows: Field current (A) Induced e.m.f. (V) 0 0157 0477 0-663 0-805 1-0 1-29 12.5 100 300 400 450 500 -550 The machine is then shunt-connected and run at 1000 rev/min with a constant field-circuit resistance of 540 Q. The armature-circuit resistance is 1 0. Deduce and plot the load characteristic of this machine, neglecting the effect of armature reaction. What is the ap- proximate value of the maximum load curront 10. The open