Methane is oxidized with air to produce formaldehyde in a continuous reactor. A competing reaction is the combustion of methane to form CO2. CH4(g) + O2 --> HCHO (g) + H2O (g) CH4(g) + 2 O2 --> CO2 (g) + 2 H2O (g) Air is supplied 35% excess based on the first reaction. The product gas contains 24 moles of formaldehyde and 11 moles carbon dioxide. (Hint: the product gas contains methane, formaldehyde, oxygen, nitrogen, carbon dioxide, water) Methane enters the reactor at 25C while air is preheated at 373K. The product gas leaves at 500K. Per 100 moles of methane entering the reactor, how much heat is removed from the reactor? ( in kJ, whole number) Given heat capacity as a function of temperature : Methane: 19.87 x 10-3 + 5.021 x 10 -5 T + 1.268 x 10 -8 T2 – 11 x 10-12 T3 (tempt unit Kelvin) Formaldehyde: 34.28 x 10-3 + 4.268 x 10 -5T -8.694 x 10-12 T3 (T unit in °C) (B) what is the total moles of the product gas?
Methane is oxidized with air to produce formaldehyde in a continuous reactor. A competing reaction is the combustion of methane to form CO2.
CH4(g) + O2 --> HCHO (g) + H2O (g)
CH4(g) + 2 O2 --> CO2 (g) + 2 H2O (g)
Air is supplied 35% excess based on the first reaction. The product gas contains 24 moles of formaldehyde and 11 moles carbon dioxide. (Hint: the product gas contains methane, formaldehyde, oxygen, nitrogen, carbon dioxide, water)
Methane enters the reactor at 25C while air is preheated at 373K. The product gas leaves at 500K. Per 100 moles of methane entering the reactor, how much heat is removed from the reactor? ( in kJ, whole number)
Given heat capacity as a function of temperature :
Methane: 19.87 x 10-3 + 5.021 x 10 -5 T + 1.268 x 10 -8 T2 – 11 x 10-12 T3 (tempt unit Kelvin)
Formaldehyde: 34.28 x 10-3 + 4.268 x 10 -5T -8.694 x 10-12 T3 (T unit in °C)
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