Make me 2 questions on relative motion in the forum with complete solutions. here is my example below of what I am expecting you to answer: NOTE: Don't copy the question below make me a similar question and then solve it as you see below how they solved it. 1.A conductor in a train travelling at 4.0 m/s (N) walks across the train at 1.2 m/s (E) to validate a ticket. If the trian car is 4.0m wide, how long does it take the conductor to reach the other side?

Make me 2 questions on relative motion in the forum with complete solutions. here is my example below of what I am expecting you to answer: NOTE: Don't copy the question below make me a similar question and then solve it as you see below how they solved it. 1.A conductor in a train travelling at 4.0 m/s (N) walks across the train at 1.2 m/s (E) to validate a ticket. If the trian car is 4.0m wide, how long does it take the conductor to reach the other side?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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1. make me one question on relative motion in the forum with complete solutions. here is my example below of what I am expecting you to answer: NOTE: Don't copy the question below make me a similar question and then solve it as you see below how they solved it. 2. Emilio is given a basketball to shoot into from a 12 m balcony, he shoots with a velocity of 6.0m/s[60° above the horizontal], and it lands into the net. What is the impact velocity of the basketball? ziy cos 60 = viy vix = (6.0m/s) cos 60 = = 3m/s(right) sin 60 viy vi viy = (6.0m/s) sin 60 = 5.19m/s (up) a = 9.81 m/s² (down) viy = 5.19m/s (up) Ad = 12.0m (down) vfy²=viy² + 2a A dy vfy² - ((5.19))+2(-9.81m/s²)(-12.0m) = vfy = √262.376 vfy = ±16. 19 m/s vfy = -16.19 a = 9.81 m/s² (down) vfy = 16.19m/s (down) (down) A dy 12.0m (down vix = 3m/s vf = √√vx² +vf² vf = √√(3m/s)² + (16.19m/s)² vf = 16.46m/s 0 tan - 1= (ufy) (16,10) 0 tan-1= 0 = 79° right79 down
1. make me one question on relative motion in the forum with complete solutions. here is my example below of what I am expecting you to answer: NOTE: Don't copy the question below make me a similar question and then solve it as you see below how they solved it. Manny is playing golf with his friend, he hits the golf ball from a 7.0m high building with a velocity of 8.0 m/s [45° above the horizontal], and it lands next to a pond. How long does it take for the golf ball to hit the ground and reach the pond? cos 45 vix viy vix = (8.0m/s) cos 45 vix = 5.65m/s (right) viy vr viy - (8.0m/s) sin 45 5.65m/s (up) sin 45 viy = = a = 9.81m/s² viy 1= 5.65m/s (up) Ad 7.0m (down vfy² = viy² + 2a A dy vfy² = ((5.65m/s) ²) + 2(-9.8 +2(-9.81m/s² vfy=√169.2625 vfy = ±13m/s vfy = -13m/s vf=vi+a At – 13m/s = 5.65m/s + (−–9.81m/s²) A t -18.65m/s -9.81m/s² 1/ 3²) (-7. At= At = 1.9s -7.0m
1. make me one question on relative motion in the forum with complete solutions. here is my example below of what I am expecting you to answer: NOTE: Don't copy the question below make me a similar question and solve that 1.A conductor in a train travelling at 4.0 m/s (N) walks across the train at 1.2 m/s (E) to validate a ticket. If the trian car is 4.0m wide, how long does it take the conductor to reach the other side? vog=? vom= 1.2 m/s(E) (1.2/4.2) vmg= 4.0 m/s(N) vog=4.2m/s(N17E) Ad At = Δυ At = 3.3s 4.0m/s 1.2m/s vog=vom+vmg =1.2m/s(E) + 4.0m/s(N) =sqrt (1.2m/s)^2 + (4.0m/s)^2 =4.2 m/s Tan-1= = 17
Hi, please show full solutions and also explain how you get the answers in physics terms so it's understandable. The correct final answers are written beside too. Thank you. 13. A ball of mass m, is stationary when a ball of mass 2m collides with it travelling with a speed of v. If the collision between the 2 balls is completely inelastic, show that the final velocity of the balls is 2/3 v.
Please show complete solution. Related rates. SOLVE ON YOUR OWN. Do not just snip or crop others solution on net. 1. Car A moves due east at 30 kph at the same instant car B is moving 5 30º E, with a speed of 60 kph. The distance from A to B is 30 km. Find how fast is the distance between then separating after one hour.
15 kilometers Questions: a. How long does it take Mario to reach school considering his average speed? b. If x represents the time it takes Mario to drive to school with the given distance of 15 kilometers, how will you represent the relationship of his speed (y) versus the time (x)? c. Mario's average speed as 30 kilometers per hour. Suppose Mario lowers his speed by 10 kilometers per hour, how long will he reach the school given the same distance? d. Suppose Mario's speed is unknown and represented by (x), he lowers his speed by 10 kilometers per hour at a distance of 15 kilometers and reaches school at 3 hours, 4 - how will you write the equation to find his average speed (x)? e. Mario's average speed was 30 kilometers per hour. He plans to drive for another 30 kilometers from school, how long will it take him to cover the whole distance (house to school to 30 kilometers from school)? f. If Mario drives another (x) kilometers from his school at an average speed of 30 kilometers per…
་ Part A A starship voyages to a distant planet 10 ly away. The explorers stay 4.0 yr, return at the same speed, and arrive back on earth 26 yr after they left. Assume that the time needed to accelerate and decelerate is negligible. What is the speed of the starship? Express your answer using two significant figures. = 0.91 Submit Previous Answers Part B Correct Important: If you use this answer in later parts, use the full unrounded value in your calculations. How much time has elapsed on the astronauts' chronometers? Express your answer using two significant figures. Η ΜΕ ΑΣΦ t = 52.4 Submit Previous Answers Request Answer ? × Incorrect; Try Again; 5 attempts remaining years
Please solve for me question the 4 number. Again I just need it the solution of question number 4.
Can you help me answer this? Solve separately by letter and explain how you get the answer. Thank you. About relative motion.
lets say we have the figure above.. help please this is our problem. a. GET THE GRAVITATIONAL FORCE THAT IT EXERTS ON THE MASS M PARTICLE (a distance of x from the centre ring) along da axis. b. lets say, that this particle will fall from its rest. because of the attraction of ring. GET THE EXPRESSION OF SPEED (passes thru the centre ring lets also assume it started a distance A that is away from the centre. thank you so much. we will upvote the answer
The question is attached to this post. This problem is noncalculator question and please give full reasoning to the answer. Please answer question 5, not 4. I attached question 4 as well because, for question 5, we need question 4.
Car A is traveling with a constant speed of 60 kph, while Car B is traveling with a constant speed of 50 kph. consider the figure below.1. which of the following is the correct vector equation to solve the speed of Car B relative to Car A? a. V[A/B] = -V[A] - V[B]b. V[A/B] = V[A] - V[B]c. V[B/A] = V[B] + V[A]d. V[B/A] = -V[B] - V[A]2. Find the speed of Car B relative to Car A