lo gravity (g) on the surfac

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter13: Universal Gravitation
Section: Chapter Questions
Problem 13.6OQ: An object of mass m is located on the surface of a spherical planet of mass M and radius R. The...
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HW help! Please make a diagram of the situation with labels! Please include a frame of reference! All variables should be defined and constant quantities included. Please put units in the equations. Please justify the answers . And only use the formulas from the givens.
THANK YOU SO MUCH!!

Kraid Kalculation
QUESTION The planet Zebes has a small ship orbiting around
it. The ship travels around the Zebes in a circular orbit.
QUESTION, ASSUME:
• The distance between the ship's center and the planet's surface is
2.00 X 10' m
• The ship has a tangential velocity of 2002 m/s
• The planet Zebes has a radius of 1.2 x 10 m
• The direction of radius (r) is (+}
QUESTION, DETERMINE:
The constant acceleration due to gravity (g) on the surface of Zebes
Transcribed Image Text:Kraid Kalculation QUESTION The planet Zebes has a small ship orbiting around it. The ship travels around the Zebes in a circular orbit. QUESTION, ASSUME: • The distance between the ship's center and the planet's surface is 2.00 X 10' m • The ship has a tangential velocity of 2002 m/s • The planet Zebes has a radius of 1.2 x 10 m • The direction of radius (r) is (+} QUESTION, DETERMINE: The constant acceleration due to gravity (g) on the surface of Zebes
Any/all* of the following relations underly the material and are hereby
GIVEN (written out for you) below:
EF = ma
f = H,N
v = lim
W = SF. dx
IFF lim
-v - v =
IFF = 0 - w = F. Ax
KE =mv?
a =
ΣW ΔΚΕ
a = lim
Δυ + ΣW
AKE
non-conservative
()-
-
IFF lim
= a
= Fdt
IFF lim
IFF E = 0 - = Ft
Ap
IFF lim
a - Ax =at + vt p = mv
%3D
-a - Ax =
IFF lim
Za
a =-
= 0
mgh
aa
=- kx
E- V ba
U =kr
ab
be
F =- G-
sin'e + cos e = 1
g z 10 m/s (On Earth)
G= 6. 67 x 10-"N-".
U. =- GMm
*Any given highlighted in RED has not been introduced in
lecture and, therefore, CANNOT be used
Transcribed Image Text:Any/all* of the following relations underly the material and are hereby GIVEN (written out for you) below: EF = ma f = H,N v = lim W = SF. dx IFF lim -v - v = IFF = 0 - w = F. Ax KE =mv? a = ΣW ΔΚΕ a = lim Δυ + ΣW AKE non-conservative ()- - IFF lim = a = Fdt IFF lim IFF E = 0 - = Ft Ap IFF lim a - Ax =at + vt p = mv %3D -a - Ax = IFF lim Za a =- = 0 mgh aa =- kx E- V ba U =kr ab be F =- G- sin'e + cos e = 1 g z 10 m/s (On Earth) G= 6. 67 x 10-"N-". U. =- GMm *Any given highlighted in RED has not been introduced in lecture and, therefore, CANNOT be used
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