Ln(rate) 0 0.003 -1 -2 بن -4 -5 -6 -7 0.0032 Ln(rate) vs 1/T 0.0034 1/T 0.0036 0.0038 y = 1815.5x-12.328 R² = 0.9187 7. Calculate the activation energy and report this value with correct units and three significant figures. Show all work. 0.004

Ln(rate) 0 0.003 -1 -2 بن -4 -5 -6 -7 0.0032 Ln(rate) vs 1/T 0.0034 1/T 0.0036 0.0038 y = 1815.5x-12.328 R² = 0.9187 7. Calculate the activation energy and report this value with correct units and three significant figures. Show all work. 0.004

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter13: Chemical Kinetics

Section: Chapter Questions

Problem 13.67QE

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Question

Ln(rate)
0
0.003
-1
-2
بن
-4
-5
-6
-7
0.0032
Ln(rate) vs 1/T
0.0034
1/T
0.0036
0.0038
y = 1815.5x-12.328
R² = 0.9187
7. Calculate the activation energy and report this value with correct units and three
significant figures. Show all work.
0.004

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