Linear Data Structures Given a list of X objects, you want to create a program that performs the following operations: • func2 Get the first (F) and last (L) object and place them both at the end of the list. e.g. ABCDE becomes BCDAE Assume that the size of the list will never change once initialized. Find the worst case time complexity for the following cases: Give both the equation AND the Big-O notation when time complexity is asked for. 1. for func2 if you were to implement the solution using a Stack? a. Equation: b. Big-O notation:
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- Arithmetic progression def arithmetic_progression(items): An arithmetic progression is a numerical sequence so that the stride between each two consecutive elements is constant throughout the sequence. For example, [4, 8, 12, 16, 20] is an arithmetic progression of length 5, starting from the value 4 with a stride of 4. Given a non-empty list items of positive integers in strictly ascending order, find and return the longest arithmetic progression whose all values exist somewhere in that sequence. Return the answer as a tuple (start, stride, n) of the values that define the progression. To ensure unique results to facilitate automated testing, if there exist several progressions of the same length, this function should return the one with the lowest start. If several progressions of equal length emanate from the lowest start, return the progression with the smallest stride. items expected results [42] (42, 0, 1) [2, 4, 6, 7, 8, 12, 17] (2, 2, 4) [1, 2, 36, 49, 50, 70, 75, 98,…Double trouble def double_trouble(items, n): Suppose, if just for the sake of argument, that the following operation is repeated n times for the given list of items: remove the first element, and append that same element twice to the end of items. Which one of the items would be removed and copied in the last operation performed? Sure, this problem could be finger-quotes “solved” by actually performing that operation n times, but the point of this exercise is to come up with an analytical solution to compute the result much faster than actually going through that whole rigmarole. To gently nudge you towards thinking in symbolic and analytical solutions, the automated tester is designed so that anybody trying to brute force their way through this problem by performing all n operations one by one for real will run out of time and memory long before receiving the answer, as will the entire universe. To come up with this analytical solution, tabulate some small cases (you can implement the…Double trouble def double_trouble(items, n): Suppose, if just for the sake of argument, that the following operation is repeated n times for the given list of items: remove the first element, and append that same element twice to the end of items. Which one of the items would be removed and copied in the last operation performed?Sure, this problem could be finger-quotes “solved” by actually performing that operation n times, but the point of this exercise is to come up with an analytical solution to compute the result much faster than actually going through that whole rigmarole. To gently nudge you towards thinking in symbolic and analytical solutions, the automated tester is designed so that anybody trying to brute force their way through this problem by performing all n operations one by one for real will run out of time and memory long before receiving the answer, as will the entire universe.To come up with this analytical solution, tabulate some small cases (you can implement the…
- struct nodeType { int infoData; nodeType * next; }; nodeType *first; … and containing the values(see image) Using a loop to reach the end of the list, write a code segment that deletes all the nodes in the list. Ensure the code performs all memory ‘cleanup’ functions.Computer Engineering HandsOn Lab: The Government of United States of America has decided to issue new currency notes with special protection features to so as to commemorate a great mathematician. They have decided to issue notes summing up to N and all the sums from 1 to N should only made by selecting some of the notes in only one unique way. With n = 5 the sets {1,1,1,1,1}, {1,2,2}, {1,1,3} are valid. Your task is to design a C++ code that output the solution in one line. Sample Input - 100 Sample Output - 3Bishops on a binge def safe_squares_bishops(n, bishops): A generalized n-by-n chessboard has been taken over by some bishops, each represented as a tuple (row, column) of the row and the column of the square the bishop stands on. Same as in the earlier version of this problem with rampaging rooks, the rows and columns are numbered from 0 to n - 1. Unlike a chess rook whose moves are axis-aligned, a chess bishop covers all squares that are on the same diagonal with that bishop arbitrarily far into any of the four diagonal compass directions. Given the board size n and the list of bishops on that board, count the number of safe squares that are not covered by any bishop. To determine whether two squares (r1, c1) and (r2, c2) are reachable from each other in one diagonal move, use abs(r1-r2) == abs(c1-c2) to check whether the horizontal distance between those squares equals their vertical distance, which is both necessary and sufficient for the squares to lie on the same diagonal. This…
- Rooks on a rampage def safe_squares_rooks(n, rooks): A generalized n-by-n chessboard has been invaded by a parliament of rooks, each rook represented as a two-tuple (row, column) of the row and the column of the square that the rook is in. Since we are again computer programmers instead of chess players and other normal folks, our rows and columns are numbered from 0 to n - 1. A chess rook covers all squares that are in the same row or in the same column. Given the board size n and the list of rooks on that board, count the number of empty squares that are safe, that is, are not covered by any rook. To achieve this in reasonable time and memory, you should count separately how many rows and columns on the board are safe from any rook. Because permuting the rows and columns does not change the answer to this question, you can imagine all these safe rows and columns to have been permuted to form an empty rectangle at the top left corner of the board. The area of that safe rectangle is…flip_matrix(mat:list)->list You will be given a single parameter a 2D list (A list with lists within it) this will look like a 2D matrix when printed out, see examples below. Your job is to flip the matrix on its horizontal axis. In other words, flip the matrix horizontally so that the bottom is at top and the top is at the bottom. Return the flipped matrix. To print the matrix to the console: print('\n'.join([''.join(['{:4}'.format(item) for item in row]) for row in mat])) Example: Matrix: W R I T X H D R L G L K F M V G I S T C W N M N F Expected: W N M N F G I S T C L K F M V H D R L G W R I T X Matrix: L C S P Expected: S P L C Matrix: A D J A Q H J C I Expected: J C I A Q H A D Jclass Solution(object): def longestCommonPrefix(self, strs): result ="" for i in strs[0]: for j in strs[1]: for k in strs[2]: if i == j and i == k: result+=i if len(result) >0: return result else: return result IndexError: list index out of range for j in strs[1]: Line 5 in longestCommonPrefix (Solution.py) ret = Solution().longestCommonPrefix(param_1) Line 31 in _driver (Solution.py) _driver() Line 41 in <module> (Solution.py) can someone explain why this is wrong?
- Subject-Object oriented programing Write a program which:• creates a new Array List• adds 5 decimal numbers to it• prints the list to the screen In the same program, use a 'for' loop to print each element of the Array List to the screen.Data structure/ C language / Graph / Dijkstra’s algorithm implement a solution of a very common issue: howto get from one town to another using the shortest route.* design a solution that will let you find the shortest paths betweentwo input points in a graph, representing cities and towns, using Dijkstra’salgorithm. Your program should allow the user to enter the input filecontaining information of roads connecting cities/towns. The programshould then construct a graph based on the information provided from thefile. The user should then be able to enter pairs of cities/towns and thealgorithm should compute the shortest path between the two cities/townsentered.Attached a file containing a list of cities/towns with the following data:Field 1: Vertex ID of the 1st end of the segmentField 2: Vertex ID of the 2nd of the segmentField 3: Name of the townField 4: Distance in KilometerPlease note that all roads are two-ways. Meaning, a record may representboth the roads from feild1 to field2…Domino cycledef domino_cycle(tiles):A single domino tile is represented as a two-tuple of its pip values, such as (2,5) or (6,6). This function should determine whether the given list of tiles forms a cycle so that each tile in the list ends with the exact same pip value that its successor tile starts with, the successor of the last tile being the first tile of the list since this is supposed to be a cycle instead of a chain. Return True if the given list of domino tiles form such a cycle, and False otherwise. tiles Expected result [(3, 5), (5, 2), (2, 3)] True [(4, 4)] True [] True [(2, 6)] False [(5, 2), (2, 3), (4, 5)] False [(4, 3), (3, 1)] False