TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT LetZdistanceTbed₂ =Pointbetween = and Id₁ =di(Z-1) (Z-1)and distance between z√ (Z+1) (2+1)aSoAsI and -1are foci of ellipse andPoint on ellipse then by definationd₁ + d₂ =c (constant)√ (z-1) (21) +As Point i2= - i√₁-i + i +1ison ellipseZZ-Z-Z+1 +(Z+1) (Z+1) = C-√zzSquasing both sidesthemis d, so thatвоC= 2√2So equation of ellipse2and I is d₂ thenon the ellipse so that Put z= i= |and zz=ZZ+Z+Z +1zz-z-Z +1 +√√ Z = + = + = +1+]+√√√1+1-1+1 = C| +i-i+|2 (ZZ+ 1) +2 √√(z{+1)²_=_= (2+²)² == √(√(2²71) ³² (2+2) ²ZZ-3Again Squeasing both sides= 8= Cz be a= 2√22(ZZ-3)² = (ZĒ+1)²_ (z+Zj²(zz) ² + 9 - 6 zz (zē)²+1+2zē−(z)²-(z)²-2z=6Zz-z²Z²8

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Let Z distance 기 be d₂ Point on ellipse between z and I d₁ = and distance = a (Z-1) (2-1) between z √ (Z+1) (2+1) As Point i so == -1 Ад I and -1 are foci of ellipse and Point on ellipse then by defination d₁ + d₂ = c (constant) √ (z-1) (1) + √ (z+1) (2+1) ZZ-Z-Z +1 is then is di 기 C= 2√2 So equation of ellipse and -1 √1-² +² +1 +√1+i-i+1 i Squaring both sides ZZ + Z + € +1 zz-z-Z+1 +√ZZ+Z+ = +1 = 2 6ZZ-Z²-Z² = 8 ²- 7² = 8 с on the ellipse so that Put z= i and ZZ = 1 is d₂ so that = c then = C = z be a = 2√√/2 2 (Z²+ 1) + 2 √(z{+1)³²_ (Z+Z) ² (zz71) 2 (2+z) 2 ZZ-3 Again Squeasing both sides 2 (ZZ-3)² = (2+1)²2²_ (Z+Z)² (zz)2+9 - 6zz (zē)²+1+2zz-(Z)²_ (€) ²³-277 8