l Resolving of Example (1-3) Two reservoirs with a difference in elevation of 15 m are connected by the three pipes in series. The pipes are 300 m long of diameter 30 cm, 150 m long of 20 cm diameter, and 200 m long of 25 cm diameter respectively. The friction factors for the three pipes are, respectively, 0.018, 0-020 and 0-019, and which account for friction and all losses. Further the contractions and expansions are sudden. Determine the flow rate in l/s. The loss co-efficient for sudden contraction from dia. 30 cm to 20 cm = 0.24.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Resolving of Example (1-3) Two reservoirs with a difference in elevation of 15 m are
connected by the three pipes in series. The pipes are 300 m long of diameter 30 cm,
150 m long of 20 cm diameter, and 200 m long of 25 cm diameter respectively. The
friction factors for the three pipes are, respectively, 0.018, 0-020 and 0-019, and which
account for friction and all losses. Further the contractions and expansions are sudden.
Determine the flow rate in l/s. The loss co-efficient for sudden contraction from dia. 30
cm to 20 cm = 0.24.
Le-L₂ (D.) ²
Le = L3 (D₁) ²
5
D3
LT. L₁ + L₂ ( D₁ ) ³ + L3 (D²₂) ³
5
5
D3
Transcribed Image Text:Use= Resolving of Example (1-3) Two reservoirs with a difference in elevation of 15 m are connected by the three pipes in series. The pipes are 300 m long of diameter 30 cm, 150 m long of 20 cm diameter, and 200 m long of 25 cm diameter respectively. The friction factors for the three pipes are, respectively, 0.018, 0-020 and 0-019, and which account for friction and all losses. Further the contractions and expansions are sudden. Determine the flow rate in l/s. The loss co-efficient for sudden contraction from dia. 30 cm to 20 cm = 0.24. Le-L₂ (D.) ² Le = L3 (D₁) ² 5 D3 LT. L₁ + L₂ ( D₁ ) ³ + L3 (D²₂) ³ 5 5 D3
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