Knowing that the radius of each pulley is 130 mm and neglecting friction, external force is 297 N. Determine the internal forces at Points J and K of the frame shown.Solution:1. FBD for frame and pulleys together:a. There areb. Sum moment about pointc. Sum all the horizonal forces to zero, solve that Ax ==d. Sum all the vertical forces to zero, yield that Ay + By2. FBD for Member AE:a. There aresupports on the frame, they are bothc. Thus Byb. Sum moment about point=a. There aresolve that Bx =d. Sum all the horizontal forces to zero, solve that ExN; direction is pointing to the3. FBD for AK to determine the internal forces on K:forces/reactions on the member AE, for a 2D body, this is staticallya. There areforces/reactions on the AK;b. Sum axial forces to zero, solve that nominal force FKd. Sum moment about pointand note that the tension force in the cable on D isc. Sum tangential forces to zero, solve that shear force VK =4. FBD for BJ to determine the internal forces on J:forces/reactions on the AK;d. Sum moment about point=b. Sum axial forces to zero, solve that nominal force FK+◆ ; all together there are=N; direction is pointing to thec. Sum tangential forces to zero, solve that shear force VK =N; direction is pointing to theN;, solve that bending moment on k is MkN; direction is pointing to theN; direction is pointing to theN; direction is pointing to thereactions on the supports, for a 2D body, this is staticallysolve that Aysolve that bending moment on J is MJ =+N; direction is pointing to theN; direction is pointing to the◆Nm; direction is pointing to the=→Nm; direction is pointing to theN; direction is pointing to the◆◆1.8 m1mD0.8 mK0.8 m 0.8 m

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Knowing that the radius of each pulley is 130 mm and neglecting friction, external force is 297 N. Determine the internal forces at Points J and K of the frame shown. Solution: 1. FBD for frame and pulleys together: a. There are b. Sum moment about point c. Sum all the horizonal forces to zero, solve that Ax= a. There are supports on the frame, they are both d. Sum all the vertical forces to zero, yield that Ay + By = 2. FBD for Member AE: c. Thus By = b. Sum moment about point , solve that By = a. There are a. There are d. Sum all the horizontal forces to zero, solve that Ex= 3. FBD for AK to determine the internal forces on K: forces/reactions on the AK; N; direction is pointing to the forces/reactions on the member AE, for a 2D body, this is statically b. Sum axial forces to zero, solve that nominal force FK = c. Sum tangential forces to zero, solve that shear force VK = d. Sum moment about point 4. FBD for BJ to determine the internal forces on J: forces/reactions on the AK; , and note that the tension force in the cable on D is all together there are N; direction is pointing to the b. Sum axial forces to zero, solve that nominal force FK = N; direction is pointing to the N; c. Sum tangential forces to zero, solve that shear force VK = N; direction is pointing to the , solve that bending moment on k is MK = N; direction is pointing to the N; direction is pointing to the reactions on the supports, for a 2D body, this is statically , solve that A, = d. Sum moment about point , solve that bending moment on J is MJ = N; direction is pointing to the + N; direction is pointing to the Nm; direction is pointing to the + ● Nm; direction is pointing to the N; direction is pointing to the 1.8m A D 0.8m K 0.8 m 0.8 m

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter6: Beams And Cables

Section: Chapter Questions

Problem 6.6P: Find the internal force systems acting on sections 1 and 2.