It) Two-block system is Problem (im given below. The mass of block one is m¡ = 3 kg and the mass of block two is m¡ = 7 kg. A force is applied on m2 to start the motion of block two knowing that block 1 doesn't move. The coefficient of static friction for all surfaces is given as 0.7. (Take g=9.8 m/s²). Tension force m. Fapplied m2 e) ( -, - , Calculate the magnitude of normal force |F N2| applied on the block 2 by the ground surface. N

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Chapter1: Units, Trigonometry. And Vectors
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k) Two-block system is
Problem 4i
given below. The mass of block one is m¡ = 3 kg
and the mass of block two is m¡ = 7 kg. A force is
applied on m2 to start the motion of block two
knowing that block 1 doesn't move. The
coefficient of static friction for all surfaces is
given as 0.7. (Take g=9.8 m/s²).
Tension force
m:
Fapplied
m2
e) (-, - , Calculate the magnitude of normal
force |F N2| applied on the block 2 by the
ground surface.
N
f) ( - .
maximum static friction force | F 2| exerted by
` Calculate the magnitude of the
the ground surface on block 2.
|F2|
N
g)\ .. -) Calculate the magnitude of the
applied force |Fapplied] that is needed just to
start the motion of the block 2.
|F applied|=
Transcribed Image Text:k) Two-block system is Problem 4i given below. The mass of block one is m¡ = 3 kg and the mass of block two is m¡ = 7 kg. A force is applied on m2 to start the motion of block two knowing that block 1 doesn't move. The coefficient of static friction for all surfaces is given as 0.7. (Take g=9.8 m/s²). Tension force m: Fapplied m2 e) (-, - , Calculate the magnitude of normal force |F N2| applied on the block 2 by the ground surface. N f) ( - . maximum static friction force | F 2| exerted by ` Calculate the magnitude of the the ground surface on block 2. |F2| N g)\ .. -) Calculate the magnitude of the applied force |Fapplied] that is needed just to start the motion of the block 2. |F applied|=
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