int hashMap: (string k) { int i = getindex(k); if (mapli) == NULL) { return -1; else { return i;
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The following hash map method should be named what?
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- BooksMan import java.util.HashMap; import java.util.ArrayList; class Book{ String title, ISBN; ArrayList authors; public Book (String title, String ISBN, String authors){ this.title = title; this.ISBN = ISBN; this.authors = new ArrayList(); if (authors != null) { String [] authorArray = authors.split(", "); for (int i = 0; i < authorArray.length; i++) { this.authors.add(authorArray[i]); } } } public String getISBN() { return ISBN; } public String getTitle() { return title; } public ArrayList getAuthors() { return authors; } } public class Main { public static HashMap buildMap(Book[] s) { HashMap books = new HashMap(); if (s != null) { // TODO Write the statements here: to manage each book from the parameter array reference to the hashmap } return books; } public static void main(String argv[]) { Book[] bookArray = new Book[4]; for (int i = 0; i < 4; i++) {…the code: class HighArray { private long[] a; private int nElems; public HighArray(int max) { a = new long[max]; nElems = 0; } public void insert(long value) { a[nElems] = value; nElems++; } public boolean find(long searchKey) { int j; for (j = 0; j < nElems; j++) if (a[j] == searchKey) break; if (j == nElems) return false; else return true; } public long getMax() { if (nElems == 0) return 01; else { long max = a[0]; for (int i = 1; i < nElems; i++) { if (a[i] > max) max = a[i]; } return max; } } public boolean delete(long value) { int j; for (j = 0; j < nElems; j++) if (value == a[j]) break; if (j == nElems) return false; else { for (int k = j; k < nElems; k++) a[k] = a[k + 1]; nElems--; return true; } } public void display() { for (int j = 0; j < nElems; j++) System.out.print(a[j] + " "); System.out.println(""); }} public class HighArrayApp { public static void main(String[] args) { int maxSize =…Java Code: Add a HashMap to your Lexer class and initialize all the keywords. Change your lexer so that it checks each string before making the WORD token and creates a token of the appropriate type if the work is a key word. When the exact type of a token is known, you should NOT fill in the value string, the type is enough. For tokens with no exact type we still need to fill in the token’s string. Rename “WORD” to “IDENTIFIER”. Strings and characters will require some additions to your state machine. Create “STRINGLITERAL” and “CHARACTERLITERAL” token types. These cannot cross line boundaries. Your lexer should throw an exception if it encounters a character that it doesn’t expect outside of a comment, string literal or character literal. Create a new exception type that includes a good error message and the token that failed. Ensure that the ToString method prints nicely. Add “line number” to your Token class. Keep track of the current line number in your lexer and populate each…
- public static ArrayList findExactString(String s, ArrayList myArray) { return null; } // Use the above method, findExactString, as a helper method to implement addWithoutDuplication method. The addWithoutDuplication method has the following properties: 1- It takes two arguments, a string s and an ArrayList myArray of type string. 2- It returns an integer which represents the number of occurrences of the string s in myArray while attempting to add it. 3- If myArray is null, it returns -1 4- If adds the string s to the end of the ArrayList myArray if the string s is not already there. public static int addwithout Duplication(String s, ArrayList myArray) { return -1;Write the following method that returns an ArrayList from a set:public static <E> ArrayList<E> setToList(Set<E> s)int binsearch (int X , int V [] , int n ) { int low , high , mid , i ; low = 0; high = n - 1; for ( i = 0; i < high ; i ++) { if( V[ i ] > V [ i +1]) return -2; } while ( low <= high ) { mid = ( low + high )/2; if ( X < V [ mid ]) high = mid - 1; else if ( X > V [ mid ]) low = mid + 1; else return mid ; } return -1; } This code takes as input a sorted array V of size n, and an integer X, if X exists in the array it will return the index of X, else it will return -1. 1. Draw a CFG for binsearch(). 2. From the CFG, identify a set of entry–exit paths to satisfy the complete statement coverage criterion. 3. Identify additional paths, if necessary, to satisfy the complete branch coverage criterion. 4. For each path identified above, derive their path predicate…
- Doctor -signature:String -doctorID:int - medicine:Arraylist +Doctor(signature:String,doctorID:int) +PrescribeMedicine():void + salary () +checkRecords():void Medicine Pharmacist -medName:String -startTime:int -dosage :int -endTime:int -date_prescribed:int - medicine:Arraylist +Medicine(medName:String,-dosage :int,date_prescribed:int) +Pharmacist (startTime:int,endTime:int) +checkForConflict():double +confirm_prescription():String +getStartTime():int +getEndTime():int +setStartTime(time:int):void +setEndTime(time1:int).voidimport java.util.HashSet; import java.util.Set; // Define a class named LinearSearchSet public class LinearSearchSet { // Define a method named linearSearch that takes in a Set and an integer target // as parameters public static boolean linearSearch(Set<Integer> set, int target) { // Iterate over all elements in the Set for () { // Check if the current value is equal to the target if () { // If so, return true } } // If the target was not found, return false } // Define the main method public static void main(String[] args) { // Create a HashSet of integers and populate integer values Set<Integer> numbers = new HashSet<>(); // Define the target to search for numbers.add(3); numbers.add(6); numbers.add(2); numbers.add(9); numbers.add(11); // Call the linearSearch method with the set…@return index of the point that is closest to the origin, which is (0, 0) * In case of a tie, return the lowest index */ public int closestToOriginIndex() { return 0; }
- package ch08.apps;import ch08.maps.*; public class HMapDriver { public static void main(String[] args) { boolean result; HMap<String, String> test; test = new HMap<String, String>(10,0.75); /*String s = null;test.put(s,"value");test.put("s",null);System.out.println("Expect 'null':\t" + test.get("s"));System.out.println("Expect 'true':\t" + test.contains("s"));test = new ArrayListMap<String, String>();*/ System.out.println("Expect 'true':\t" + test.isEmpty()); System.out.println("Expect '0':\t" + test.size()); System.out.println("Expect 'null':\t" + test.put("1", "One")); System.out.println("Expect 'false':\t" + test.isEmpty()); System.out.println("Expect '1':\t" + test.size()); System.out.println("Expect 'One':\t" + test.put("1", "One")); System.out.println("Expect 'false':\t" + test.isEmpty()); System.out.println("Expect '1':\t" + test.size()); test.put("2", "Two"); test.put("3", "Three");…maxLength Language/Type: Related Links: Java Set collections Set Write a method maxLength that accepts as a parameter a Set of strings, and that returns the length of the longest string in the set. If your method is passed an empty set, it should return 0. 1 9 10 Method: Write a Java method as described, not a complete program or class. N345678 2Java: Please solve without using Hash set. The class will contain the following static methods: reverseS – A method that displays a string reversely on the console using the following signature: public static void reverseS(String s) printSub1 – print all substrings of a string (duplicated substrings are allowed, but loops are not allowed). The method signature: public static void printSub1(String s) printSub2 – print all substrings of a string (duplicated substrings are not allowed, but loops are allowed). The method signature: public static void printSub2(String s) Note: All methods should be RECURSIVE. Any predefined classes that are based on Set are not allowed. Allow the user to input the string! In the main method, read a string from the user and output the reversed string and substrings to the screen: Sample Run: Please input a string: abcd The reversed string: dcba The substrings of the input string: abcd abc ab a b bc b c bcd bc b c cd c d The substrings of the input string: a…