Instruction: Find the following AH for the reaction below. 1. 2SO2 + 2P + 5C12 → 2SOCI2 + 2POCI3 AH = ? Given: SOCI2 + H20 → SO2+ 2HCI AH = +10.3 KJ PCI3 + 1/202 → POCI3 AH = -325.7 KJ P+ 3/2 Cl2 → PCI3 AH = -306.7 KJ 4HCI + O2 → 2C12 + 2H2O AH = -202.6 KJ 2. ACIS() - ACl3{g) + Cl2(g) AH = ? Given: A4(s) + 6C12(g) → 4AC]3{g) AH = -2439 kJ 4ACIS(g) → A4(s) + 10CI2(e) AH = 3438 kJ 3. 2H(s) + 202(g) - 2HO2(s) AH = ? Given: 2HO2(s) + O2(g) → 2HO3(s) AH = -309 kJ 2H(s) + 302(g) → 2HO3(s) AH = -1357 kJ
Instruction: Find the following AH for the reaction below. 1. 2SO2 + 2P + 5C12 → 2SOCI2 + 2POCI3 AH = ? Given: SOCI2 + H20 → SO2+ 2HCI AH = +10.3 KJ PCI3 + 1/202 → POCI3 AH = -325.7 KJ P+ 3/2 Cl2 → PCI3 AH = -306.7 KJ 4HCI + O2 → 2C12 + 2H2O AH = -202.6 KJ 2. ACIS() - ACl3{g) + Cl2(g) AH = ? Given: A4(s) + 6C12(g) → 4AC]3{g) AH = -2439 kJ 4ACIS(g) → A4(s) + 10CI2(e) AH = 3438 kJ 3. 2H(s) + 202(g) - 2HO2(s) AH = ? Given: 2HO2(s) + O2(g) → 2HO3(s) AH = -309 kJ 2H(s) + 302(g) → 2HO3(s) AH = -1357 kJ
Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter4: Polar Bonds, Polar Reactions
Section: Chapter Questions
Problem 29CTQ
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Question
Topic: Hess's Law
![Instruction: Find the following AH for the reaction below.
1. 2SO2 + 2P + 5CI2 → 2SOCI2 + 2POCI3
AH = ?
Given:
SOCI2 + H20 → SO2 + 2HCI
AH = +10.3 KJ
PCI3 + 1/202→ POC3
AH = -325.7 KJ
P + 3/2 Cl2 → PCI3
AH = -306.7 KJ
4HCI + O2 → 2C12+ 2H2O
AH = -202.6 KJ
2. ACIS(e) → ACI3(g) + Cl2(e)
AH = ?
Given:
A4(s) + 6CI2(g) → 4AC]3(g)
AH = -2439 kJ
4ACI5(g) → A4(s) + 10C22(g)
AH = 3438 kJ
3. 2H(s) + 202(g)
2HO2(s)
AH = ?
Given:
2HO2(s) + O2(g)
→ 2HO3(s)
AH = -309 kJ
2H(s) + 302(g) –→ 2HO3(s)
AH = -1357 kJ](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7c6dcbb9-454c-4cd0-8575-83dece80c6f3%2F32063a13-7ad4-4b9b-b48d-24f94dc55b7f%2Ff1i4zpn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Instruction: Find the following AH for the reaction below.
1. 2SO2 + 2P + 5CI2 → 2SOCI2 + 2POCI3
AH = ?
Given:
SOCI2 + H20 → SO2 + 2HCI
AH = +10.3 KJ
PCI3 + 1/202→ POC3
AH = -325.7 KJ
P + 3/2 Cl2 → PCI3
AH = -306.7 KJ
4HCI + O2 → 2C12+ 2H2O
AH = -202.6 KJ
2. ACIS(e) → ACI3(g) + Cl2(e)
AH = ?
Given:
A4(s) + 6CI2(g) → 4AC]3(g)
AH = -2439 kJ
4ACI5(g) → A4(s) + 10C22(g)
AH = 3438 kJ
3. 2H(s) + 202(g)
2HO2(s)
AH = ?
Given:
2HO2(s) + O2(g)
→ 2HO3(s)
AH = -309 kJ
2H(s) + 302(g) –→ 2HO3(s)
AH = -1357 kJ
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